05 js利用ajax向服务器发送请求并返回json值

创建一个php

$json = '';
$data = array();
$con =mysqli_connect($servername, $username, $password, $dbname);//连接服务器
class User
{
    public $name;
    public $chengji;
}
$sql = "SELECT * FROM xxxx";//获取数据库列表
$result = $con->query($sql);

if($result){
//echo "查询成功";
    while ($row = mysqli_fetch_array($result))
    {
        $user = new User();
        $user->name = $row["name"];
        $user->chengji = $row["chengji"];
        $data[]=$user;
    }
    $json = json_encode($data);//把数据转换为JSON数据.
    echo "$json";
}else{
    echo "查询失败";
}
?>

ajax获取json数据

var settings = {
"url": "php在服务器的地址",
"method": "GET",//用get请求服务器
"timeout": 0,
dataType: "json",//数据类型为json
};

$.ajax(settings).done(function (response) {

var json = response;
for (var index in json) {  
console.log(json[index].属性, " ", json[index].属性2);

};
console.log(response);
});