Merge Two Sorted Lists & Remove Nth Node From End of List
1.合并两个排好序的list
Merge Two Sorted Lists
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
2.删除list倒数第n个元素
Remove Nth Node From End of List
Given a linked list, remove the nth node from the end of list and return its head.
For example,
Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5.
Note:
Given n will always be valid.
Try to do this in one pass.
两个问题合在一个工程里面测试
package com.rust.datastruct;
public class MergeTwoSortedLists {
public static ListNode mergeTwoSortedLists(ListNode l1, ListNode l2) {
ListNode r1 = new ListNode(0);
ListNode res = r1;
ListNode t1 = l1;//java 中这样的赋值操作,对了l1操作等同于对t1操作
ListNode t2 = l2;
while (t1 != null && t2 != null){
if (t1.val <= t2.val) {
r1.next = t1;
t1 = t1.next;
} else {
r1.next = t2;
t2 = t2.next;
}
r1 = r1.next;
}
if (t1 != null) {
r1.next = t1;
}
if (t2 != null) {
r1.next = t2;
}
res = res.next;
return res;
}
/**
* @param head
* @param n
* @return ListNode
*/
public static ListNode removeNthFromEnd(ListNode head, int n) {
if (n == 0) return head;
ListNode fakeNode = head;
int count = 0;
while (fakeNode != null) {
fakeNode = fakeNode.next;
count++;
}
fakeNode = head;
if (n == count) {
head = head.next;
return head;
} else {
for (int i = 0; i < count; i++) {
if (i + n + 1== count) {
System.out.println(fakeNode.val);
ListNode cut = fakeNode.next.next;
fakeNode.next = cut;
count--;
continue;
}
fakeNode = fakeNode.next;
}
}
return head;
}
public static void main(String args[]){
ListNode l1 = new ListNode(0);
ListNode l2 = new ListNode(1);
ListNode p1 = l1;
ListNode p2 = l2;
/*initial the list*/
for (int i = 2; i <= 10; i++) {
if (i%2 == 0) {
p1.next = new ListNode(i);
p1 = p1.next;
} else {
p2.next = new ListNode(i);
p2 = p2.next;
}
}
p1 = l1;
p2 = l2;
System.out.println("input List l1 and l2");
showData(l1, l2);//after show,l1 and l2 value didn't change!
System.out.println("mergeTwoLists(l1, l2) -->");
ListNode res = mergeTwoSortedLists(l1, l2);
/** test mergeTwoSortedLists start ************/
while (res.next != null) {// res is destroyed
System.out.print(res.val + "\t");
res = res.next;
}
System.out.println(res.val);
System.out.println("After merge");
/** End ***********************************/
/** test removeNthFromEnd start **************/
showData(l1, l2);
// use l2 to test
int n = 1;
l2 = removeNthFromEnd(l2,n);
showData(l1, l2);
/** End ***********************************/
}
/**
* Print the ListNode
* @param l1 ListNode
* @param l2 ListNode
*/
public static void showData(ListNode l1, ListNode l2){
System.out.println("l1 -->");
while (l1.next != null) {
System.out.print(l1.val + "\t");
l1 = l1.next;
}
System.out.println(l1.val);
System.out.println("l2 -->");
while (l2.next != null) {
System.out.print(l2.val + "\t");
l2 = l2.next;
}
System.out.println(l2.val);
System.out.println("/************************************/");
}
}
//Definition for singly-linked list.
class ListNode {
int val;
ListNode next;
ListNode(int x) { val = x; }
}
输出:
input List l1 and l2
l1 -->
0 2 4 6 8 10
l2 -->
1 3 5 7 9
/************************************/
mergeTwoLists(l1, l2) -->
0 1 2 3 4 5 6 7 8 9 10
After merge
l1 -->
0 1 2 3 4 5 6 7 8 9 10
l2 -->
1 2 3 4 5 6 7 8 9 10
/************************************/
9
l1 -->
0 1 2 3 4 5 6 7 8 9
l2 -->
1 2 3 4 5 6 7 8 9
/************************************/
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