Mapper查询技巧
Sql字段动态比较判断
<sql id="getUserInfoList_body">
SELECT * from userinfo
<dynamic prepend="WHERE">
<isNotNull prepend="AND" property="id"> a.id=#id#</isNotNull>
<isNotNull prepend="AND" property="userName"> a.userName like concat('%', #userName#, '%') </isNotNull>
<isNotNull prepend="AND" property="inschoolTimeEnd"> a.inschoolTime < #inschoolTimeEnd# </isNotNull>
<isNotNull property="roleID">
<isEqual property="roleID" compareValue="3" prepend="AND">
addrProvinceID in (SELECT areaID FROM co_user_area WHERE adminID = #adminID#)</isEqual>
<isEqual property="roleID" compareValue="4" prepend="AND">
addrCityID in (SELECT areaID FROM co_user_area WHERE adminID = #adminID#)</isEqual>
</isNotNull>
</dynamic>
ORDER BY a.id DESC
</sql>
sql语句返回主键id
<insert id=""> //注意无需resultClass
…
<selectKey resultClass="int" keyProperty="id">
SELECT @@IDENTITY AS id
</selectKey>
</insert> public Integer insert(Invoice invoice) throws DAOException {
return (Integer)getSqlMapClientTemplate().insert("insert",invoice);
}
sql时间范围查询条件
//一
< isNotNull prepend="AND" property="createStartDateStr">
CONVERT(varchar(100), kb.createDate , 23) >= #createStartDateStr#
</isNotNull>
<isNotNull prepend="AND" property="createEndDateStr">
CONVERT(varchar(100),kb.createDate,23) <=#createEndDateStr#
</isNotNull> //二
<isNotNull prepend="AND" property="startTime">
kc.createDate >= #startTime#
</isNotNull>
<isNotNull prepend="AND" property="endTime">
<![CDATA[kc.createDate <= #endTime#]]>
</isNotNull> //三
<isNotNull prepend="AND" property="startTime">
CONVERT(varchar(100), kb.createDate , 23) >= #startTime#
</isNotNull>
<isNotNull prepend="AND" property="endTime">
CONVERT(varchar(100), kb.createDate , 23) <= #endTime#
</isNotNull>
sql每月数据统计
SELECT
COUNT(DISTINCT kes.userID) AS examCount,
CONVERT(nvarchar(7), kesd.createTime, 120) AS month
FROM kp_out_system kos WITH (NOLOCK)
LEFT JOIN kp_exam_score kes WITH (NOLOCK)
ON kes.outSystemSign = kos.outSystemSign
LEFT JOIN kp_exam_score_detail kesd WITH (NOLOCK)
ON kesd.examScoreID = kes.id AND kesd.valid = 1
< isNotNull prepend="AND" property="startTime"> kesd.createTime >= #startTime# </isNotNull>
<isNotNull prepend="AND" property="endTime"> kesd.createTime <= #endTime# </isNotNull>
WHERE kos.status = 1
<isNotNull prepend="AND" property="outSystemSign"> kos.outSystemSign=#outSystemSign# </isNotNull>
AND kos.outSystemSign IS NOT NULL AND kos.sysAreaID IS NOT NULL AND kesd.createTime IS NOT NULL
GROUP BY CONVERT(nvarchar(7), kesd.createTime, 120)
ORDER BY CONVERT(nvarchar(7), kesd.createTime, 120)
sql对sum()结果判空
SELECT ISNULL(SUM(myTable.thesisCount),0) AS thesisCount FROM (
SELECT
COUNT(kuu.id) AS thesisCount,
ISNULL(kos.outSystemName, '无') AS outSystemName
FROM kp_out_system kos WITH (NOLOCK)
LEFT JOIN kp_user_upload_thesis kuu WITH (NOLOCK) ON kuu.outSystemSign = kos.outSystemSign AND kuu.valid = 1
WHERE kos.status = 1
<isNotNull prepend="AND" property="outSystemSign"> kuu.outSystemSign = #outSystemSign# </isNotNull>
AND kos.outSystemSign IS NOT NULL AND kos.sysAreaID IS NOT NULL
GROUP BY ISNULL(kos.outSystemName, '无')
) AS myTable
验证某个属性是否已存在(修改信息时用)
select COUNT(*) from ... where id != #id# and ... = #...#
sql数组传参(in)
//Action代码
if (null != studyID && 2 == studyID.intValue()) {
Integer[] studyIDs = new Integer[] { 2,3, 4 };
userInfo.setStudyIDs(studyIDs);
} else {
userInfo.setStudyID(studyID);
} //Xml文件
<isNotNull prepend="AND" property="studyID">
a.studyID=#studyID#
</isNotNull>
<isNotNull prepend="AND" property="studyIDs">
a.studyID in
<iterate property="studyIDs" open="(" close=")" conjunction=",">
#studyIDs[]#
</iterate>
</isNotNull>
Int类型拼接需要使用cast()
SELECT (SELECT DISTINCT
CAST(studyID AS varchar) + ','
FROM kp_study_type
WHERE outSystemSign = 'drivingcoach' AND valid = 1
FOR xml PATH (''))
AS studyIDs,
ISNULL(
SUM(CASE
WHEN b.isPass = 1 THEN 1 ELSE 0
END), 0) AS isPassCount,
ISNULL(
SUM(CASE
WHEN b.isOpen = 1 OR b.isOpen = 3 THEN 1 ELSE 0
END), 0) AS isOpenCount,
ISNULL(
SUM(CASE
WHEN b.isOpen = 1 OR b.isOpen = 3 THEN 0 ELSE 1
END), 0) AS isNotOpenCount
FROM kp_study_type a WITH (NOLOCK)
INNER JOIN kp_select_studyType b WITH (NOLOCK)
ON a.studyID = b.studyID AND b.valid = 1
INNER JOIN kp_user_info kui WITH (NOLOCK)
ON kui.ID = b.userID AND kui.valid = 1
LEFT JOIN (SELECT
k.studyID,
k.userID,
SUM(k.studyTimes) studyTimes,
SUM(CASE
WHEN k.studyTimes >= k.studyTime * 60 THEN 1 ELSE 0
END) coursefinishCount,
COUNT(k.courseID) courseCount
FROM (SELECT
r.studyID,
t.userID,
SUM(t.studyTimes) AS studyTimes,
r.courseID,
r.studyTime
FROM kp_studyCourse_relation r WITH (NOLOCK)
LEFT JOIN kp_course c WITH (NOLOCK)
ON r.courseID = c.id
LEFT JOIN kp_study_course_time t WITH (NOLOCK)
ON c.courseNumber = t.courseNumber AND t.studyID = r.studyID
WHERE r.valid = 1 AND c.valid = 1 AND t.id IS NOT NULL
GROUP BY r.studyID,
t.userID,
r.courseID,
r.studyTime) k
GROUP BY k.studyID,
k.userID) e
ON a.studyID = e.studyID AND b.userID = e.userID
WHERE a.valid = 1 AND a.studyID IN (SELECT DISTINCT
studyID
FROM kp_select_studyType
WHERE outerSystemSign = 'drivingcoach' AND valid = 1 AND isOpen = 1)
sql截取字符串
SELECT DISTINCT
ISNULL(SUBSTRING(areaID, 1, 6), 0) AS areaID
FROM kp_user_info
或
SELECT
TOP 10
kui.username
FROM kp_user_info kui WITH (NOLOCK)
LEFT JOIN dic_area dc WITH (NOLOCK)
ON RIGHT(kui.areaID, 6) = dc.areaID
地区搜索,传参设置
if(null != provinceID && !"000000".equals(provinceID)){
productOrder.setAreaID(provinceID);
}
if(null!=cityID && cityID != ""){
//数据库存储为110000:110101,依据存储方式设置
productOrder.setAreaID(provinceID+":"+cityID);
}
<dynamic prepend="">
<isNotNull prepend="AND" property="areaID">
kui.areaID like #areaID# + '%'
</isNotNull>
</dynamic>
以...开头
*
FROM computer
WHERE sex = '男' AND LEFT(name, 1) IN ('李', '陈')
或
SELECT
*
FROM computer
WHERE sex = '男'
(and name like '李__'or name like '陈__')
跨库复制表数据
//-1-
SET IDENTITY_INSERT cdel_jxjy_flat20171106..op_ip_login_control ON;
//-2-
INSERT INTO cdel_jxjy_flat20171106..op_ip_login_control (id, ip, notes, valid, creator, createTime)
SELECT * FROM cdel_jxjy_flat0725..op_ip_login_control
Mapper查询技巧的更多相关文章
- SQL高级查询技巧
SQL高级查询技巧 1.UNION,EXCEPT,INTERSECT运算符 A,UNION 运算符 UNION 运算符通过组合其他两个结果表(例如 TABLE1 和 TABLE2)并消去表中任何重 ...
- google查询技巧
技巧一:使用正确的方法 无论你是使用一个简单或是高级的Google搜索,在此都存在你应该使用的某种可靠的方法.遵循适当的方法你就能获得非常准确的结果:要是忽略这条建议的话,你也许就会看到大量不相关的结 ...
- MySQL翻页查询技巧
在查询大量数据库,一般都会采用翻页.自然会想到offset跟limit. 今天知道了一个技巧,用id查询.因为id是主键,查起来很快. 思路是:给id一个区间做where条件,将数据分隔成几份,然后每 ...
- SQLServer多条件查询技巧
2019-10-15 13:31:04 在实际项目开发中,有很多页面都会出现多条件查询功能,类似于这种情况: 牵扯到数据就少不了数据库了.这么多条件的查询,如果要用常规的if else来写判断逻辑的 ...
- 2020想进大厂你不得不了解的MySQL意外事件的查询技巧
导读:数据库是导致应用系统运行缓慢的常见原因.面对数据库引性能问题,很多开发者或者DBA却束手无策.本文作者经过多年的实际经验,整理了一些材料,将Linux环境下MySQL性能突发事件问题排查技巧分享 ...
- 【转】sql各种查询技巧
高级查询在数据库中用得是最频繁的,也是应用最广泛的. Ø 基本常用查询 --select select * from student; --all 查询所有 select all sex from ...
- SQL高级查询技巧(两次JOIN同一个表,自包含JOIN,不等JOIN)
掌握了这些,就比较高级啦 Using the Same Table Twice 如下面查询中的branch字段 SELECT a.account_id, e.emp_id, b_a.name open ...
- Oracle优化查询技巧
1. WHERE子句中的连接顺序:Oracle采用自下而上的顺序解析WHERE子句,根据这个原理,表之间的连接必须写在其他WHERE条件之前, 那些可以过滤掉最大数量记录的条件必须写在WHERE子句的 ...
- hql查询技巧
要擅于利用对象之间映射的集合去查与其关联的对象,而不是直接在dao层重新写查询的方法,其实,hibernate正是对复杂查询的一种解放,既然有现成的东西,何必再去闭门造车,而且造出来的还是个旧车. 查 ...
随机推荐
- [LeetCode]129. Sum Root to Leaf Numbers路径数字求和
DFS的标准形式 用一个String记录路径,最后判断到叶子时加到结果上. int res = 0; public int sumNumbers(TreeNode root) { if (root== ...
- MySQL索引优化,explain详细讲解
前言:这篇文章主要讲 explain 如何使用,还有 explain 各种参数概念,之后会讲优化 一.Explain 用法 模拟Mysql优化器是如何执行SQL查询语句的,从而知道Mysql是如何处理 ...
- JVM 常用命令行工具
本文部分摘自<深入理解 Java 虚拟机第三版> 基础故障处理工具 Java 开发人员肯定都知道 JDK 的 bin 目录下有许多小工具,这些小工具除了用于编译和运行 Java 程序外,打 ...
- 大数据量查询容易OOM?试试MySQL流式查询
一.前言 程序访问 MySQL 数据库时,当查询出来的数据量特别大时,数据库驱动把加载到的数据全部加载到内存里,就有可能会导致内存溢出(OOM). 其实在 MySQL 数据库中提供了流式查询,允许把符 ...
- TurtleBot3使用课程-第一节b(北京智能佳)
目录 1.模拟运行TurtleBot 2 1.1 ROS安装和设置2 1.1.1 turtlebot3 在Gazebo中模拟 3 1.1.1.1用于Gazebo的ROS包装 3 1.1.1.2 tur ...
- mysql The used table type doesn’t support FULLTEXT indexes 解决方案 (phpstudy 会出现),coten不会
mysql The used table type doesn't support FULLTEXT indexes 是不支持全文索引,解决方案: 1.停掉mysql服务2.打开my.ini,搜索de ...
- three.js canvas内场景生成图片 canvas生成图片
第一种最简单的方法: 1 threeBox.render();//重点 解决拿到图片后为黑色 2 3 let src=threeBox.renderer.domElement.toDataURL(); ...
- LeetCode105 从前序和中序序列构造二叉树
题目描述: 根据一棵树的前序遍历与中序遍历构造二叉树. 注意:你可以假设树中没有重复的元素. 例如,给出 前序遍历 preorder = [3,9,20,15,7] 中序遍历 inorder = [9 ...
- 【Flutter】容器类组件之填充
前言 Padding可以给其子节点添加填充(留白). 接口描述 class EdgeInsets extends EdgeInsetsGeometry { // 分别指定四个方向的填充 const E ...
- Jenkins上实现Python + Jenkins + Allure Report 接口自动化测试持续集成,最终测试报告用allure-report进行展示
项目介绍 接口功能测试应用:http://www.weather.com.cn/data/cityinfo/<city_code>.html 测试功能:获取对应城市的天气预报 源码:Pyt ...