Little Bishops uva861
Little Bishops
A bishop is a piece used in the game of chess which is played on a board of square grids. A bishop can only move diagonally from its current position and two bishops attack each other if one is on the path of the other. In the following figure, the dark squares represent the reachable locations for bishop B1 form its current position. The figure also shows that the bishops B1 and B2 are in attacking positions whereas B1 andB3 are not. B2 and B3 are also in non-attacking positions.
Now, given two numbers n and k, your job is to determine the number of ways one can put k bishops on an n × n chessboard so that no two of them are in attacking positions.
Input
The input file may contain multiple test cases. Each test case occupies a single line in the input file and contains two integers n (1 ≤ n ≤ 8) and k(0 ≤ k ≤ n2).
A test case containing two zeros for n and k terminates the input and you won’t need to process this particular input.
Output
For each test case i
#include"iostream"
#include"cstring"
#include"algorithm"
using namespace std;
const int N=;
int b[N+],w[N+],rb[N+][],rw[N+][];
void init_chessboard(int n)
{
memset(b,,sizeof(b));
memset(w,,sizeof(w));
for(int i=;i<=n;i++)
for(int j=;j<=n;j++)
{
if((i+j)&)
w[(i+j)>>]++;
else
b[(i+j)>>]++;
}
}
void bishops(int n,int k,int c[N+],int R[N+][])
{
for(int i=;i<=n;i++)
R[i][]=;
for(int j=;j<=k;j++)
R[][j]=;
for(int i=;i<=n;i++)
for(int j=;j<=c[i];j++)
R[i][j]=R[i-][j]+R[i-][j-]*(c[i]-j+);
}
int main()
{
int n,k,ans;
while(scanf("%d%d",&n,&k)!=EOF)
{
if(n==&&k==)
break;
init_chessboard(n);
sort(b+,b+n+);
sort(w+,w+n);
bishops(n,k,b,rb);
bishops(n-,k,w,rw);
ans=;
for(int i=;i<=k;i++)
ans+=rb[n][i]*rw[n-][k-i];
printf("%d\n",ans);
}
return ;
}
n the input print a line containing the total number of ways one can put the given number of bishops on a chessboard of the given size so that no two of them are in attacking positions. You may safely assume that this number will be less than 1015.
Sample Input
8 6
4 4
0 0
Sample Output
5599888
260
Little Bishops uva861的更多相关文章
- codeforces Gargari and Bishops(很好的暴力)
/* 题意:给你一个n*n的格子,每一个格子都有一个数值!将两只bishops放在某一个格子上, 每一个bishop可以攻击对角线上的格子(主对角线和者斜对角线),然后会获得格子上的 数值(只能获取一 ...
- CodeForces463C Gargari and Bishops(贪心)
CodeForces463C Gargari and Bishops(贪心) CodeForces463C 题目大意: 在国际象棋的棋盘上放两个主教,这个两个主教不能攻击到同一个格子,最后的得分是这 ...
- B. Wet Shark and Bishops(思维)
B. Wet Shark and Bishops time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
- Codeforces 612B. Wet Shark and Bishops 模拟
B. Wet Shark and Bishops time limit per test: 2 seconds memory limit per test: 256 megabytes input: ...
- Wet Shark and Bishops(思维)
Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are nu ...
- GYM - 101147 F.Bishops Alliance
题意: 一个n*n的棋盘,有m个主教.每个主教都有自己的权值p.给出一个值C,在棋盘中找到一个最大点集.这个点集中的点在同一条对角线上且对于点集中任意两点(i,j),i和j之间的主教数(包括i,j)不 ...
- codeforces 463C. Gargari and Bishops 解题报告
题目链接:http://codeforces.com/contest/463/problem/C 题目意思:要在一个 n * n 大小的棋盘上放置两个bishop,bishop可以攻击的所有位置是包括 ...
- Codeforces--621B--Wet Shark and Bishops(数学)
B. Wet Shark and Bishops time limit per test 2 seconds memory limit per test 256 megabytes input ...
- Bishops Alliance—— 最大上升子序列
原题链接:http://codeforces.com/gym/101147/problem/F 题意:n*n的棋盘,给m个主教的坐标及其私有距离p,以及常数C,求位于同一对角线上满足条件:dist(i ...
随机推荐
- SpannableString 记录(转)
引用 http://blog.csdn.net/rockcoding/article/details/7231756 TextView是用来显示文本的,有时需要给TextView中的个别字设置为超链接 ...
- Hbase 基本命令
启动Hbase:./start-hbase.sh 进入Hbase shell控制台:./hbase shell 查看所有表 list 查看数据库状态:status 查看数据库版本:vers ...
- pyinstaller使用小结
安装pyinstaller pip install -U pyinstaller 生成控制台程序 pyinstaller ./example.py 在当前目录的dist文件夹内可以找到编译成功的程序 ...
- 了解RFC协议号
RFC是Request For Comment的缩写,意即“请求注解”,是由IETF管理,所有关于Internet的正式标准都以文档出版,但不是所有的RFC都是正式的标准,很多RFC的目的只是为了提供 ...
- 使用bootstrap的html文件转换成jsp…
问题:使用bootstrap的html文件转换成jsp时表单高度变窄 解决方法: 将jsp中html文档类型修改为<!DOCTYPE html> 问题即可解决. 也就是bootstrap只 ...
- HDU 5778 abs (枚举)
abs 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5778 Description Given a number x, ask positive ...
- Gym 100507A About Grisha N. (水题)
About Grisha N. 题目链接: http://acm.hust.edu.cn/vjudge/contest/126546#problem/A Description Grisha N. t ...
- display:none;与visibility:hidden;的区别
visibility:隐藏对应的元素但不挤占该元素原来的空间.display:隐藏对应的元素并且挤占该元素原来的空间. 下面来看visibility和dispaly的一些参数 visibility用来 ...
- 如何解决paramiko执行与否的问题
使用paramiko执行一些耗时比较长的命令的时候会出现实际上命令没有执行完就跳出的问题,怎么才能准确的判断命令执行完与否很重要,通过试验发现如下的方法可以解决这个难题: dabao_cmd = 'e ...
- CodeForces 706B Interesting drink (二分查找)
题意:给定 n 个数,然后有 m 个询问,每个询问一个数,问你小于等于这个数的数有多少个. 析:其实很简单么,先排序,然后十分查找,so easy. 代码如下: #pragma comment(lin ...