【LeetCode 208】Implement Trie (Prefix Tree)
Implement a trie with insert, search, and startsWith methods.
Note:
You may assume that all inputs are consist of lowercase letters a-z.
思路:
构建一个简单的字典树,要求实现插入、查找、查找前缀三个操作。这里使用map实现对子树的构建(一方面方便查找,另一方面是懒 - -!),但是效率并不是太高,LeetCode上提交后跑了147ms,不是很理想,不过不影响对字典树这种树形结构的理解。
class TrieNode {
public:
// Initialize your data structure here.
TrieNode(char c):ch(c), isEnd(false){}
map<char, TrieNode *> childNode;
char ch;
bool isEnd;
};
class Trie {
public:
Trie() {
root = new TrieNode('#');
}
// Inserts a word into the trie.
void insert(string s) {
TrieNode *t = root;
//从root遍历待插入字符串,若c存在则继续向下遍历,反之则新建一个分支
for(int i = ; i < s.length(); i++)
{
char c = s[i];
map<char, TrieNode*>::iterator it = t->childNode.find(c);
if(it == t->childNode.end())
{
TrieNode *newNode = new TrieNode(c);
t->childNode.insert(make_pair(c, newNode));
t = newNode;
}
else
{
t = t->childNode[c];
}
}
t->isEnd = true;
}
// Returns if the word is in the trie.
bool search(string key) {
TrieNode *s = root;
//从root遍历待查找字符串,若c存在则向下遍历,反之则不存在
for(int i = ; i < key.length(); i++)
{
char c = key[i];
map<char, TrieNode*>::iterator it = s->childNode.find(c);
if(it == s->childNode.end())
return false;
else
s = s->childNode[c];
}
//返回最后一个结点的状态,判断是否为一个word
return s->isEnd;
}
// Returns if there is any word in the trie
// that starts with the given prefix.
bool startsWith(string prefix) {
TrieNode *s = root;
//与search一致
for(int i = ; i < prefix.length(); i++)
{
char c = prefix[i];
map<char, TrieNode*>::iterator it = s->childNode.find(c);
if(it == s->childNode.end())
return false;
else
s = s->childNode[c];
}
//只要找到即返回true
return true;
}
private:
TrieNode* root;
};
【LeetCode 208】Implement Trie (Prefix Tree)的更多相关文章
- leetcode面试准备:Implement Trie (Prefix Tree)
leetcode面试准备:Implement Trie (Prefix Tree) 1 题目 Implement a trie withinsert, search, and startsWith m ...
- LeetCode OJ:Implement Trie (Prefix Tree)(实现一个字典树(前缀树))
Implement a trie with insert, search, and startsWith methods. 实现字典树,前面好像有道题做过类似的东西,代码如下: class TrieN ...
- 【LeetCode】208. Implement Trie (Prefix Tree)
Implement Trie (Prefix Tree) Implement a trie with insert, search, and startsWith methods. Note:You ...
- 【刷题-LeetCode】208. Implement Trie (Prefix Tree)
Implement Trie (Prefix Tree) Implement a trie with insert, search, and startsWith methods. Example: ...
- 字典树(查找树) leetcode 208. Implement Trie (Prefix Tree) 、211. Add and Search Word - Data structure design
字典树(查找树) 26个分支作用:检测字符串是否在这个字典里面插入.查找 字典树与哈希表的对比:时间复杂度:以字符来看:O(N).O(N) 以字符串来看:O(1).O(1)空间复杂度:字典树远远小于哈 ...
- [LeetCode] 208. Implement Trie (Prefix Tree) ☆☆☆
Implement a trie with insert, search, and startsWith methods. Note:You may assume that all inputs ar ...
- LeetCode208 Implement Trie (Prefix Tree). LeetCode211 Add and Search Word - Data structure design
字典树(Trie树相关) 208. Implement Trie (Prefix Tree) Implement a trie with insert, search, and startsWith ...
- 【LeetCode】208. Implement Trie (Prefix Tree) 实现 Trie (前缀树)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:Leetcode, 力扣,Trie, 前缀树,字典树,20 ...
- 【leetcode】208. Implement Trie (Prefix Tree 字典树)
A trie (pronounced as "try") or prefix tree is a tree data structure used to efficiently s ...
随机推荐
- 用 Xamarin for VS 创建 aar 文件的绑定
预备工作:相关aar文件,Xamarin for VS一份.我这里以Android中挺火的 MaterialDesignLibrary 为例. 1.首先,创建一个Xamarin Binding Lib ...
- LintCode 字符串比较
比较两个字符串A和B,确定A中是否包含B中所有的字符.字符串A和B中的字符都是大写字母: 给出 A = "ABCD" B = "AABC", 返回 false ...
- lintcode 中等题:k Sum ii k数和 II
题目: k数和 II 给定n个不同的正整数,整数k(1<= k <= n)以及一个目标数字. 在这n个数里面找出K个数,使得这K个数的和等于目标数字,你需要找出所有满足要求的方案. 样例 ...
- [z]Google SPDY介绍
转自 http://blog.csdn.net/marcky/article/details/7728662 本文主要是参考Google SPDY项目主页的一些文档总结而来,目的整体上介绍SPDY协议 ...
- Tomcat部署Web应用方法总结
转载:http://m.blog.csdn.net/blog/u012516903/15741727 Tomcat部署Web应用方法总结 在Tomcat中部署Java Web应用程序有两种方式:静态部 ...
- tomcat version
Tomcat version 6.0 only supports J2EE 1.2, 1.3, 1.4, and Java EE 5 Web modules 转自:http://jingwang0 ...
- 写个Python练练手吧
在Python的交互式命令行写程序,好处是一下就能得到结果,坏处是没法保存,下次还想运行的时候,还得再敲一遍. 所以,实际开发的时候,我们总是使用一个文本编辑器来写代码,写完了,保存为一个.py文件, ...
- 254. Factor Combinations
题目: Numbers can be regarded as product of its factors. For example, 8 = 2 x 2 x 2; = 2 x 4. Write a ...
- HDU5087——Revenge of LIS II(BestCoder Round #16)
Revenge of LIS II Problem DescriptionIn computer science, the longest increasing subsequence problem ...
- 示例:Servlet读取文件内容并在页面打印输出
package com.mhb; import java.io.BufferedReader; import java.io.File; import java.io.FileReader; impo ...