Java for LeetCode 064 Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
解题思路:
dp问题,和上一题一样,JAVA实现如下:
static public int minPathSum(int[][] grid) {
int[] v = new int[grid[0].length];
v[0]=grid[0][0];
for (int i = 1; i < v.length; i++)
v[i] = grid[0][i]+v[i-1];
for (int i = 1; i < grid.length; i++) {
v[0] += grid[i][0];
for (int j = 1; j < v.length; j++)
v[j] = Math.min(v[j], v[j - 1]) + grid[i][j];
}
return v[v.length - 1];
}
Java for LeetCode 064 Minimum Path Sum的更多相关文章
- [Leetcode Week9]Minimum Path Sum
Minimum Path Sum 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/minimum-path-sum/description/ Descr ...
- 【leetcode】Minimum Path Sum
Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to b ...
- 【LeetCode】064. Minimum Path Sum
题目: Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right w ...
- LeetCode 64. Minimum Path Sum(最小和的路径)
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which ...
- [LeetCode] 64. Minimum Path Sum 最小路径和
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which ...
- LeetCode 64 Minimum Path Sum
Problem: Given a m x n grid filled with non-negative numbers, find a path from top left to bottom ri ...
- 【leetcode】Minimum Path Sum(easy)
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which ...
- 【题解】【矩阵】【DP】【Leetcode】Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which ...
- C#解leetcode 64. Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which ...
随机推荐
- 【HDU 1757】 A Simple Math Problem
题 Description Lele now is thinking about a simple function f(x). If x < 10 f(x) = x. If x >= 1 ...
- PLSQL中配置Oracle方法
在服务器上,用PL/SQL连接Oracle数据库时,出现了一个问题,提示: Initialization error Could not load "F:\oracle\bin\oci.dl ...
- BZOJ-3229 石子合并 GarsiaWachs算法
经典DP?稳T 3229: [Sdoi2008]石子合并 Time Limit: 3 Sec Memory Limit: 128 MB Submit: 426 Solved: 202 [Submit] ...
- Tomcat Can't load AMD 64-bit .dll on a IA 32
Java.lang.UnsatisfiedLinkError: C:\apache\apache-tomcat-7.0.14\bin\tcnative-1.dll: Can't load AMD 64 ...
- IOS 面试
1. #import , #include的区别 @import防止类的重复引用,#import 确定一个文件只能被导入一次,这使在递归包含中不会出现问题. @class一般用于头文件中需要声明该类的 ...
- javascript “||”、“&&”的灵活运用
主要介绍了||和 &&的作用 1.|| 和Java中不一样 代表的是 如果左边的true就返回左边 否则返回右边 2.&& 和java中不一样 代表的是 如果左边返回的 ...
- java 内存分析
Java堆内存(heap memory)的十个要点: 1. Java堆内存是操作系统分配给JVM的内存的一部分. 2. 当我们创建对象时,它们存储在Java堆内存中. 3. 为了便于垃圾回收,Java ...
- 初学Hibernate之Query扩展
1.hql参数化查询,不明确值类型的用setParameter方法:明确查询结果为一条记录的用uniqueResult方法查询 注意,参数化查询中方法setString 或 setParameter如 ...
- [LeetCode] Binary Tree Preorder/Inorder/Postorder Traversal
前中后遍历 递归版 /* Recursive solution */ class Solution { public: vector<int> preorderTraversal(Tree ...
- gdb命令与调试方法
单线程 http://www.cnblogs.com/lidabo/p/5629830.html 编译程序一定要加-g选项 gcc -g test.c -o test 进入gdb调试:gdb 程序名 ...