Leetcode 190 Reverse Bits 位运算

反转二进制

 class Solution {
 public:
     uint32_t reverseBits(uint32_t n) {
         uint32_t ans = ;
         for (int  i = ; i<; ++i,n >>=){
             ans = (ans<< )|(n & );
         }
         return ans;
     }
 };