For a Maximum Segment Tree, which each node has an extra value max to store the maximum value in this node's interval.

Implement a modify function with three parameter root, index and value to change the node's value with [start, end] = [index, index] to the new given value. Make sure after this change, every node in segment tree still has the max attribute with the correct value.

Have you met this question in a real interview? Yes
Example
For segment tree: [1, 4, max=3]
/ \
[1, 2, max=2] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=3]
if call modify(root, 2, 4), we can get: [1, 4, max=4]
/ \
[1, 2, max=4] [3, 4, max=3]
/ \ / \
[1, 1, max=2], [2, 2, max=4], [3, 3, max=0], [4, 4, max=3]
or call modify(root, 4, 0), we can get: [1, 4, max=2]
/ \
[1, 2, max=2] [3, 4, max=0]
/ \ / \
[1, 1, max=2], [2, 2, max=1], [3, 3, max=0], [4, 4, max=0]
Note
We suggest you finish problem Segment Tree Build and Segment Tree Query first. Challenge
Do it in O(h) time, h is the height of the segment tree.
 /**
* Definition of SegmentTreeNode:
* public class SegmentTreeNode {
* public int start, end, max;
* public SegmentTreeNode left, right;
* public SegmentTreeNode(int start, int end, int max) {
* this.start = start;
* this.end = end;
* this.max = max
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
*@param root, index, value: The root of segment tree and
*@ change the node's value with [index, index] to the new given value
*@return: void
*/
public void modify(SegmentTreeNode root, int index, int value) {
// write your code here
if (root.start == root.end) {
root.max = value;
return;
}
int mid = (root.start + root.end)/2;
if (index <= mid) modify(root.left, index, value);
else modify(root.right, index, value);
root.max = Math.max(root.left.max, root.right.max);
}
}

Lintcode: Segment Tree Modify的更多相关文章

  1. Segment Tree Modify

    For a Maximum Segment Tree, which each node has an extra value max to store the maximum value in thi ...

  2. [LintCode] Segment Tree Build II 建立线段树之二

    The structure of Segment Tree is a binary tree which each node has two attributes startand end denot ...

  3. [LintCode] Segment Tree Build 建立线段树

    The structure of Segment Tree is a binary tree which each node has two attributes start and end deno ...

  4. Lintcode: Segment Tree Query II

    For an array, we can build a SegmentTree for it, each node stores an extra attribute count to denote ...

  5. Lintcode: Segment Tree Query

    For an integer array (index from 0 to n-1, where n is the size of this array), in the corresponding ...

  6. Lintcode: Segment Tree Build

    The structure of Segment Tree is a binary tree which each node has two attributes start and end deno ...

  7. 203. Segment Tree Modify

    最后更新 二刷 08-Jan-2017 利用线段树来更改,找到更改的NODE,然后更改那个brach上的所有max值. 首先确定recursion的终止条件 然后通过判断大小来找方向 找到NODE之后 ...

  8. Lintcode247 Segment Tree Query II solution 题解

    [题目描述] For an array, we can build a Segment Tree for it, each node stores an extra attribute count t ...

  9. 『线段树 Segment Tree』

    更新了基础部分 更新了\(lazytag\)标记的讲解 线段树 Segment Tree 今天来讲一下经典的线段树. 线段树是一种二叉搜索树,与区间树相似,它将一个区间划分成一些单元区间,每个单元区间 ...

随机推荐

  1. bug 发表文章不显示图片

    bug 描述: 现象是我们这不能发布图片, 测试说患教方向是可以正常发布图片的(还是要感激测试,正是他们鞭策我们不断挑战困难,解决之,从而提高自己姿势水平). 图片没上传上去, 服务端协助查找发现没调 ...

  2. html轮播效果的实现

    要实现如下图的效果 点击可以选择图片:不点击的时候自动轮播:并且点击完后再次自动轮播. 思路:如同在房子里透过窗子看路过的火车一样,窗子是不动的,但火车是陆续经过窗子的,所以透过窗子可以看到依次看完所 ...

  3. oracle EBS 资产定义

    一.资产定义也就是江项目任务上的特定(能生成资产的)物料按照一定格式生成资产信息,其中每个独立物料生成一条资产,具体操作步骤如下: 1.省本部库存超级用户系统内生成领料单.审批领料单.最后进行出库处理 ...

  4. Error executing aapt: Return code -1073741819

    在做andrid项目的时候,本来想把a项目中的a功能模块复制到b项目中,但是复制过程中出现xml文件id的问题, Error executing aapt: Return code -10737418 ...

  5. 通过驱动向打印机发送一段(ESC)控制指令

    这个功能看起来挺奇葩的, 写这个是因为有客户在使用驱动连接票据打印机, 但是又要开钱箱, 驱动里只能每张单据都开钱箱, 而这个打印机又不是只打印结帐单 所以就需要用软件控制打印机开钱箱 票据打印机一般 ...

  6. nrf51822-配对绑定实现过程

    关于配对绑定的一些原理内容这里不再重复介绍,看之前的几篇文档,静态密码,动态密码,连接时触发配对就可以了. 配对绑定的内容可能比较难懂,升入的学习需要去看规范,将前面的几篇相关文档看一遍实验一边再去看 ...

  7. AutoHotKey使用:空格键坏了怎么办?

    ;RCtrl:: RAlt:: Send, {space} Return http://ahkscript.org/ https://autohotkey.com/download/

  8. 设计模式:策略模式(Strategy)

    定   义:它定义了算法家族,分别封装起来,让它们之间可以互相替换,此模式让算法的变化, 不会影响到使用算法的客户. 示例:商场收银系统,实现正常收费.满300返100.打8折.......等不同收费 ...

  9. ArcGIS API for Silverlight动态标绘的实现

    原文:ArcGIS API for Silverlight动态标绘的实现 1.下载2个dll文件,分别是: ArcGISPlotSilverlightAPI.dll 和 Matrix.dll 其下载地 ...

  10. qq临时会话代码修改

    使用:http://wpa.qq.com/msgrd?V=1&Uin=965745468&Site=www.***.com&Menu=yes提示 抱歉,无法发起临时会话,您可以 ...