暴力破解unix/linux平台上采用crypt加密的口令

 # coding=utf-8

 '''
 暴力破解crypt模块加密的密码
 '''

 import crypt
 import optparse

 usage = 'Usage: %prog [optinos] -p password.txt -d dictionary.txt'
 parser = optparse.OptionParser(usage,version=1.0)
 parser.add_option('-p',dest='pFile',action='store',
                   help='加密后的口令存放文件')
 parser.add_option('-d',dest='dFile',action='store',
                   help='字典文件')
 (options,args) = parser.parse_args()

 def dection_passwords(password):
    salt = password[:2]
    dfile = open(options.dFile)
    for word in dfile:
         word = word.strip('\r\n')
         cryptWord = crypt.crypt(word,salt)
         if cryptWord == password:
             print '找到密码,密码是：',word
             return
    print '未找到密码！'
    return

 def main():
    passfile = open(options.pFile)
    for password in passfile:
         password = password.strip('\r\n')
         if password != '':
             dection_passwords(password)

 if __name__ == '__main__':
    main()

运行后的结果是：

 python ForceCrackCrypt.py -p /root/Desktop/password.txt -d /root/Desktop/dictionary.txt
 找到密码,密码是：
 找到密码,密码是：
 找到密码,密码是： abc123