BNU 51002 BQG's Complexity Analysis
模拟
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<algorithm>
using namespace std; const int maxn=+;
char t1[maxn],t2[maxn];
int g1,g2,h1,h2; int main()
{
int T;
scanf("%d",&T);
while(T--)
{
g1=g2=h1=h2=;
scanf("%s%s",t1,t2); if(t1[]=='n') g1=;
if(t1[]=='^')
{
g1=;
for(int i=;;i++)
{
if(t1[i]>=''&&t1[i]<='') g1=g1*+t1[i]-'';
else break;
}
} int pos=-;
int len=strlen(t1);
for(int i=;t1[i];i++)
{
if(i+<len&&t1[i]=='l'&&t1[i+]=='o'&&t1[i+]=='g'&&t1[i+]=='n')
{
h1=;
pos=i+;
break;
}
}
if(pos!=-)
{
int sum=;
for(int i=pos;i<len;i++)
{
if(t1[i]>=''&&t1[i]<='') sum=sum*+t1[i]-'';
else break;
}
h1=max(h1,sum);
} if(t2[]=='n') g2=;
if(t2[]=='^')
{
g2=;
for(int i=;;i++)
{
if(t2[i]>=''&&t2[i]<='') g2=g2*+t2[i]-'';
else break;
}
} pos=-;
len=strlen(t2);
for(int i=;t2[i];i++)
{
if(i+<len&&t2[i]=='l'&&t2[i+]=='o'&&t2[i+]=='g'&&t2[i+]=='n')
{
h2=;
pos=i+;
break;
}
}
if(pos!=-)
{
int sum=;
for(int i=pos;i<len;i++)
{
if(t2[i]>=''&&t2[i]<='') sum=sum*+t2[i]-'';
else break;
}
h2=max(h2,sum);
} // printf("%d %d\n",g1,h1);
// printf("%d %d\n",g2,h2); if(g1<g2) printf("First\n");
else if(g1>g2) printf("Second\n");
else
{
if(h1<h2) printf("First\n");
else if(h1>h2) printf("Second\n");
else printf("Both\n");
} }
return ;
}
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