[LeetCode&Python] Problem 118. Pascal's Triangle
Given a non-negative integer numRows, generate the first numRows of Pascal's triangle.

In Pascal's triangle, each number is the sum of the two numbers directly above it.
Example:
Input: 5
Output:
[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]
class Solution(object):
def generate(self, numRows):
"""
:type numRows: int
:rtype: List[List[int]]
"""
if numRows==0:
return []
ans=[[1]]
for i in range(1,numRows):
j=0
row=[]
while j<1+i:
if j==0 or j==i:
row.append(1)
else:
row.append(ans[i-1][j-1]+ans[i-1][j])
j+=1
ans.append(row)
return ans
[LeetCode&Python] Problem 118. Pascal's Triangle的更多相关文章
- 【leetcode❤python】118. Pascal's Triangle
#-*- coding: UTF-8 -*-#杨辉三角class Solution(object): def generate(self, numRows): "&quo ...
- LeetCode Array Easy 118. Pascal's Triangle
Description Given a non-negative integer numRows, generate the first numRows of Pascal's triangle. I ...
- 【leetcode❤python】119. Pascal's Triangle II
#-*- coding: UTF-8 -*-#杨辉三角返回给定行#方法:自上而下考虑问题,从给定的一行计算出下一行,则给定行数之后,计算的最后一行就是求解的最后一行class Solution(obj ...
- leetcode 118. Pascal's Triangle 、119. Pascal's Triangle II 、120. Triangle
118. Pascal's Triangle 第一种解法:比较麻烦 https://leetcode.com/problems/pascals-triangle/discuss/166279/cpp- ...
- Leetcode#118. Pascal's Triangle(杨辉三角)
题目描述 给定一个非负整数 numRows,生成杨辉三角的前 numRows 行. 在杨辉三角中,每个数是它左上方和右上方的数的和. 示例: 输入: 5 输出: [ [1], [1,1], [1,2, ...
- LN : leetcode 118 Pascal's Triangle
lc 118 Pascal's Triangle 118 Pascal's Triangle Given numRows, generate the first numRows of Pascal's ...
- 118. Pascal's Triangle
题目: Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, ...
- LeetCode(119) Pascal's Triangle II
题目 Given an index k, return the kth row of the Pascal's triangle. For example, given k = 3, Return [ ...
- [LeetCode]题解(python):118 Pascal's Triangle
题目来源 https://leetcode.com/problems/pascals-triangle/ Given numRows, generate the first numRows of Pa ...
随机推荐
- Linux系统组成
1 系统组成 BootLoader:操作系统引导程序 内核: 文件系统:应用程序(用户开发的.网上下载的) 2 安装USB驱动 dongry@d-linux:~$ insmod usb_dnw.ko ...
- bzoj1133: [POI2009]Kon
bzoj1133: [POI2009]Kon 链接 https://www.lydsy.com/JudgeOnline/problem.php?id=1133 思路 f[i][k]表示前i个,选了k个 ...
- LeetCode in action
(1) Linked List: 2-add-two-numbers,2.cpp 19-remove-nth-node-from-end-of-list,TBD 21-merge-two-sorted ...
- _map_char_stats
可以控制玩家进入地图后进行属性平衡. `comment` 备注 `map` 地图ID `vip`vip等级 `shengming`生命 `liliang` 力量 `minjie` 敏捷 `zhili` ...
- poj 3304 Segments 线段与直线相交
Segments Time Limit: 1000MS Memory Limit: 65536K Description Given n segments in the two dim ...
- .net中文分词 jieba.NET
简介 平时经常用Python写些小程序.在做文本分析相关的事情时免不了进行中文分词,于是就遇到了用Python实现的结巴中文分词.jieba使用起来非常简单,同时分词的结果也令人印象深刻,有兴趣的可以 ...
- leecode第一百六十九题(求众数)
class Solution { public: void quick_sort(vector<int>& nums,int res,int res_end) { )//错过,不能 ...
- itsdangerous
将字典进行加密.解密 通过私钥保证安全性 serializer=TimedJSONWebSignatureSerializer(私钥,过期时间) dumps(字典)=====>返回加密字符串 l ...
- RNN流程
1.记号 2.前向计算,第二张图是第一张图的公式的简化.其中a称之为隐状态 3.计算代价函数
- 环境准备—之—linux下安装jdk
本文大部分转自 https://www.cnblogs.com/Dylansuns/p/6974272.html openjdk与jdk的区别 ----反正不一样,要不名字也不会不相同了 https ...