1060 Are They Equal (25 分)

1060 Are They Equal (25 分)

 

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123×10​5​​ with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.

Input Specification:

Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10​100​​, and that its total digit number is less than 100.

Output Specification:

For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10^k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding.

Sample Input 1:

3 12300 12358.9

Sample Output 1:

YES 0.123*10^5

Sample Input 2:

3 120 128

Sample Output 2:

NO 0.120*10^3 0.128*10^3

#include<bits/stdc++.h>
using namespace std;

int n;
string a,b;

const int maxn=;

struct bign{
    string d;
    int cnt;
};

bign change(string str,int k){

    bool flag=false;

    bign ans;

    int len=(int)str.size();

    int i=;

    while(i<len&&str[i]=='')
    {
        i++;
    }

    int pos1=-,pos2=-; 

    while(i<len){
        if(str[i]=='.')
            pos2=i;
        else if(str[i]!=''||flag){
            ans.d+=str[i];
            if(pos1==-)
                pos1=i;

            flag=true;    

        }    

        i++;
    }

    if(i>=len&&pos2==-)
        pos2=len;

    if(pos2>pos1)
        ans.cnt=pos2-pos1;
    else
        ans.cnt=pos2-pos1+;

    //cout<<pos1<<endl<<pos2<<endl;

    int anslen=(int)ans.d.size();

    if(anslen>=k)
        ans.d=ans.d.substr(,k);
    else{
        int h=k-anslen;
        while(h--)
            ans.d+='';
    }

    if(flag==false)
        ans.cnt=;

    return ans;

}

bool judge(bign a,bign b){
    if(a.d==b.d&&a.cnt==b.cnt)
        return true;
    else
        return false;
}

void print(bign a){
    cout<<" 0."<<a.d<<"*10^"<<a.cnt;
}

int main(){
    cin>>n;
    cin>>a>>b;

    bign ansa,ansb;

    ansa=change(a,n);
    ansb=change(b,n);

    bool flag = judge(ansa,ansb);

    if(flag){
        cout<<"YES";
        print(ansa);
    }

    else{
        cout<<"NO";
        print(ansa);
        print(ansb);

    }

    return ;

}