题目来源


https://leetcode.com/problems/spiral-matrix/

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.


题意分析


Input: a matrix

Output: a list

Conditions: 蛇形输出


题目思路


自己本来在想有没有一些不一样的算法,然后发现直接右下左上顺序做就好了,看到一个博客的分类做得不错,重点是要看边界情况,直接看代码。


AC代码(Python)


 class Solution(object):
def spiralOrder(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: List[int]
"""
if matrix == []:
return []
up = 0
left = 0
down = len(matrix) - 1
right = len(matrix[0]) - 1 direct = 0 res = [] while True:
if direct == 0:
for i in range(left, right + 1):
res.append(matrix[up][i])
up += 1
if direct == 1:
for i in range(up, down + 1):
res.append(matrix[i][right])
right -= 1
if direct == 2:
for i in range(right, left - 1, -1):
res.append(matrix[down][i])
down -= 1
if direct == 3:
for i in range(down, up -1, -1):
res.append(matrix[i][left])
left += 1
if up > down or left > right:
return res
direct = (direct + 1) % 4

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