31. Next Permutation

Problem's Link

----------------------------------------------------------------------------

Mean:

给定一个数列,求这个数列字典序的下一个排列.

analyse:

next_permutation函数的运用.

Time complexity: O(N)

view code

class Solution
{
public:
   void nextPermutation(vector<int>& nums)
   {
       if(next_permutation(nums.begin(),nums.end()))
           return;
       else
       {
           sort(nums.begin(),nums.end());
           return;
       }
   }
};

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