Courses
Courses
Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2681 Accepted Submission(s): 1238
Problem Description
Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to determine whether it is possible to form a committee of exactly P students that satisfies simultaneously the conditions:
. every student in the committee represents a different course (a student can represent a course if he/she visits that course)
. each course has a representative in the committee
Your program should read sets of data from a text file. The first line of the input file contains the number of the data sets. Each data set is presented in the following format:
P N
Count1 Student1 1 Student1 2 ... Student1 Count1
Count2 Student2 1 Student2 2 ... Student2 Count2
......
CountP StudentP 1 StudentP 2 ... StudentP CountP
The first line in each data set contains two positive integers separated by one blank: P (1 <= P <= 100) - the number of courses and N (1 <= N <= 300) - the number of students. The next P lines describe in sequence of the courses . from course 1 to course P, each line describing a course. The description of course i is a line that starts with an integer Count i (0 <= Count i <= N) representing the number of students visiting course i. Next, after a blank, you'll find the Count i students, visiting the course, each two consecutive separated by one blank. Students are numbered with the positive integers from 1 to N.
There are no blank lines between consecutive sets of data. Input data are correct.
The result of the program is on the standard output. For each input data set the program prints on a single line "YES" if it is possible to form a committee and "NO" otherwise. There should not be any leading blanks at the start of the line.
An example of program input and output:
Sample Input
2
3 3
3 1 2 3
2 1 2
1 1
3 3
2 1 3
2 1 3
1 1
Sample Output
YES
NO
Source
Southeastern Europe 2000
#include<stdio.h>
#include<string.h>
int P,N;
bool G[][],visit[];
int match[];
bool DFS(int k)
{
int t;
for (int i=;i<=N;i++)
if (G[k][i] && !visit[i])
{
visit[i]=;
t=match[i];
match[i]=k;
if (t==- || DFS(t)) return true;
match[i]=t;
}
return false;
}
int Max_match()
{
int ans=;
memset(match,-,sizeof(match));
for (int i=;i<=P;i++)
{
memset(visit,,sizeof(visit));
if (DFS(i)) ans++;
}
return ans;
}
int main()
{
int T;
scanf("%d",&T);
while (T--)
{
memset(G,,sizeof(G));
scanf("%d%d",&P,&N);
for (int i=;i<=P;i++)
{
int cp;
scanf("%d",&cp);
for (int j=;j<=cp;j++)
{
int x;
scanf("%d",&x);
G[i][x]=;
}
}
if (Max_match()==P) printf("YES\n");
else printf("NO\n");
}
return ;
}
Courses的更多相关文章
- poj 2239 Selecting Courses (二分匹配)
Selecting Courses Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 8316 Accepted: 3687 ...
- POJ 1469 COURSES
COURSES Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 20478 Accepted: 8056 Descript ...
- HDOJ 1083 Courses
Hopcroft-Karp算法模板 Courses Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (J ...
- HDU-----(1083)Courses(最大匹配)
Courses Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total S ...
- POJ 1469 COURSES(二部图匹配)
COURSES Time Limit: 1000MS Memory ...
- Doing well in your courses ---- a guide by Andrej Karpathy
Doing well in your courses a guide by Andrej Karpathy Here is some advice I would give to younger st ...
- Windows Kernel Security Training Courses
http://www.codemachine.com/courses.html#kerdbg Windows Kernel Internals for Security Researchers Thi ...
- poj 1469 COURSES(匈牙利算法模板)
http://poj.org/problem?id=1469 COURSES Time Limit: 1000MS Memory Limit: 10000K Total Submissions: ...
- hdoj 1083 Courses【匈牙利算法】
Courses Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total S ...
随机推荐
- codeforces 258div2C Predict Outcome of the Game
题目链接:http://codeforces.com/contest/451/problem/C 解题报告:三个球队之间一共有n场比赛,现在已经进行了k场,不知道每个球队的胜场是多少,如三个球队的胜场 ...
- NGUI无限滑动
http://www.unity蛮牛.com/blog-9383-1391.html 最近由于工作需要,就开始研究NGUI滑动.刚开始参考NGUI自带的循环滑动,利用隐藏和显示,提高GPU的渲染,但是 ...
- Python strip、lstrip和rstrip的用法
Python中strip用于去除字符串的首尾字符,同理,lstrip用于去除左边的字符,rstrip用于去除右边的字符. 这三个参数都可以传入一个参数,指定要去除的首尾字符. 需要注意的是,传入的是一 ...
- Ubuntu上安装gtk2.0不能安装的问题,“下列的软件包有不能满足的依赖关系”
zez@localhoss:~$ sudo apt-get install libgtk2.0-dev正在读取软件包列表... 完成正在分析软件包的依赖关系树 正在读取状态信息... 完成 ...
- 使用nginx的proxy_cache做网站缓存
为什么要做web cache,我想大家最主要的是解决流量的压力.随着网站流量的提升,如果只是单台机器既处理静态文件,又处理动态脚本,显然效率很难上升,不能处理日益上涨的流量压力.与此同时某些网站的页面 ...
- GIT的标准文档 使用和服务介绍
http://www.kancloud.cn/kancloud/how-to-use-github/42192 1. 探索GitHub 熟悉Git的人几乎都知道并喜欢GitHub,反过来GitHub也 ...
- Remove Nth Node From End of List
Given a linked list, remove the nth node from the end of list and return its head. Notice The minimu ...
- iOS 中使用Block时需要注意的retain circle
现在在ios中,block是越来越多了.自己在类中定义block对象时,需要注意block对象的使用方法,防止产生retain circle,导致内存泄露. 现在分析一下产生retain circle ...
- iOS __block类型变量作用域
看下图 在c语言中,2个独立的函数是不可能互相访问局部变量的,但是__block提供了这个功能,它不单单能读变量,还可以对变量进行写!上图说明,block获得了i最后的真实值5,没有只取得0,这都是& ...
- Java for LeetCode 144 Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary t ...