MATLAB中多个一维数组的合并

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https://blog.csdn.net/u013538664/article/details/37673711

1、一维数组直接合并
       题目：
           数组work1[x1,x2——,xn]，work2[y1,y2——,yn]，如今要生成一个数组work3。
       work3中的数据为[x1,x2,x3--xn,y1,y2--yn];

       合并方法：
           直接将两个矩阵合并：
             A = [1,2,3,4];
             B = [-1,-2,-3,-4];
             C = zeros(1,size(B,2)+size(A,2));     %这句能够不要;
             C = [A, B];

    2、一维数组交叉合并：
       题目：
           数组work1[x1,x2——,xn]，work2[y1,y2——,yn]。如今要生成一个数组work3，
       work3中的数据为[x1,y1,x2,y2——,xn,yn];
      
       合并方法一:
           A = [1,2,3,4];
           B = [-1,-2,-3,-4];
           C = zeros(1,size(B,2)+size(A,2));
           C(1:2:end) = A;
           C(2:2:end) = B
          
           C =
                1    -1     2    -2     3    -3     4    -4

       解法二：
           A = [1,2,3,4];
           B = [-1,-2,-3,-4];
           C=[A' B']';
           C=reshape(C, 1, length(A)+length(B));
          
           C =
                1    -1     2    -2     3    -3     4    -4

 

       解法三：

           对于解法二改进：

           c=reshape([A;B],1,[])；

           这里要注意，仅仅能在v7以上的版本号才干使用此法。

 

       解法四：
           A = [1,2,3,4];
           B = [-1,-2,-3,-4];
           C=kron(A,[1 0])+kron(B,[0 1]);
          
           C =
                1    -1     2    -2     3    -3     4    -4
      非常多技巧。试总结以上的方案：
          -------------------------------------
          A = [1,2,3,4];
          B = [-1,-2,-3,-4];
          ----------------- 1 -----------------
          C = zeros(1,size(B,2)+size(A,2));
          C(1:2:end) = A;
          C(2:2:end) = B;
          C=C(:);
          ------------------2 -----------------
          C=[A' B']';
          C=reshape(C, 1, length(A)+length(B));
          ------------------3-------------------
          c=reshape([A;B],1,[])
          ------------------4-------------------
          C=kron(A,[1 0])+kron(B,[0 1]);
          --------------------------------------