2069. Hard Rock

Time limit: 1.0 second
Memory limit: 64 MB
Ilya is a frontman of the most famous rock band on Earth. Band decided to make the most awesome music video ever for their new single. In that music video Ilya will go through Manhattan standing on the top of a huge truck and playing amazing guitar solos. And during this show residents of the island will join in singing and shaking their heads. However, there is a problem. People on some streets hate rock.
Recall that Manhattan consists of n vertical and m horizontal streets which form the grid of (n − 1)×(m − 1) squares. Band’s producer conducted a research and realized two things. First, band’s popularity is constant on each street. Second, a popularity can be denoted as an integer from 1 to 109. For example, if rockers go along the street with popularity equal to 109 then people will greet them with a hail of applause, fireworks, laser show and boxes with... let it be an orange juice. On the other hand, if rockers go along the street with popularity equal to 1 then people will throw rotten tomatoes and eggs to the musicians. And this will not help to make the most awesome music video!
So, a route goes from the upper left corner to the bottom right corner. Let us define the route coolness as the minimal popularity over all streets in which rockers passed non-zero distance. As you have probably guessed, the musicians want to find the route with the maximal coolness. If you help them then Ilya will even give you his autograph!

Input

In the first line there are integers n and m (2 ≤ nm ≤ 105), separated by space. These are the numbers of vertical and horizontal streets, respectively.
In the following n lines there are popularity values (one value on each line) on vertical streets in the order from left to right.
In the following m lines there are popularity values (one value on each line) on horizontal streets in the order from top to bottom.
It is guaranteed that all popularity values are integers from 1 to 109.

Output

Output a single integer which is a maximal possible route coolness.

Samples

input output
2 3
4
8
2
7
3
4
4 3
12
4
12
3
21
5
16
12

Notes

Explanation of the first sample (the "coolest" route is highlighted):
Problem Author: Oleg Merkurev (prepared by Alexander Borzunov)
Problem Source: Ural Regional School Programming Contest 2015
Difficulty: 159
 
题意:一个方格图,共有n+m条线,一个人从左上角走到右下角,问使路径上最小值最大。
分析:
这个人要么先横着走,走到某个点,然后下到最底部,然后再横着走到终点
要么先竖着走,走到某个点,然后横着走到最右部,然后再竖着走到终点
以上直觉是对的,但是我证明了下
 
证明:如果最优路径不是这样的
假设最优路径是先竖着走(跟先横着走是对称情况,同理可以证明先横着走的)
那么它一定要在某个点横着走的,
也就是说,前两步我们可以跟答案一样,
考虑到最优路径跟我们不一样,
如果最优路径的最后一步是竖着走的,那么我们的路径走过的边最优路径都走了,答案不可能比其劣
如果最优路径最后一步是横着走的,那么我们可以先竖着走到最下部,然后横着走,答案也不可能比其劣
也就说我们这样走的方法就是最优答案
 
 
 

ural 2069. Hard Rock的更多相关文章

  1. URAL 2069 Hard Rock (最短路)

    题意:给定 n + m 个街道,问你从左上角走到右下角的所有路的权值最小的中的最大的. 析:我们只要考虑几种情况就好了,先走行再走列和先走列再走行差不多.要么是先横着,再竖着,要么是先横再竖再横,要么 ...

  2. 【找规律】URAL - 2069 - Hard Rock

    题解及证明:http://www.cnblogs.com/StupidBoy/p/5241258.html #include<cstdio> #include<algorithm&g ...

  3. URAL 1936 Roshambo 题解

    http://acm.timus.ru/problem.aspx?space=1&num=1936 F - Roshambo Time Limit:1000MS Memory Limit:65 ...

  4. 后缀数组 POJ 3974 Palindrome && URAL 1297 Palindrome

    题目链接 题意:求给定的字符串的最长回文子串 分析:做法是构造一个新的字符串是原字符串+反转后的原字符串(这样方便求两边回文的后缀的最长前缀),即newS = S + '$' + revS,枚举回文串 ...

  5. ural 2071. Juice Cocktails

    2071. Juice Cocktails Time limit: 1.0 secondMemory limit: 64 MB Once n Denchiks come to the bar and ...

  6. ural 2073. Log Files

    2073. Log Files Time limit: 1.0 secondMemory limit: 64 MB Nikolay has decided to become the best pro ...

  7. ural 2070. Interesting Numbers

    2070. Interesting Numbers Time limit: 2.0 secondMemory limit: 64 MB Nikolay and Asya investigate int ...

  8. ural 2068. Game of Nuts

    2068. Game of Nuts Time limit: 1.0 secondMemory limit: 64 MB The war for Westeros is still in proces ...

  9. ural 2067. Friends and Berries

    2067. Friends and Berries Time limit: 2.0 secondMemory limit: 64 MB There is a group of n children. ...

随机推荐

  1. 三、jQuery--jQuery基础--jQuery基础课程--第6章 jQuery 事件与应用

    1.页面加载时触发ready()事件 ready()事件类似于onLoad()事件,但前者只要页面的DOM结构加载后便触发,而后者必须在页面全部元素加载成功才触发,ready()可以写多个,按顺序执行 ...

  2. 并发用户数与 TPS 之间的关系

    1.  背景 在做性能测试的时候,很多人都用并发用户数来衡量系统的性能,觉得系统能支撑的并发用户数越多,系统的性能就越好:对TPS不是非常理解,也根本不知道它们之间的关系,因此非常有必要进行解释. 2 ...

  3. 通过btn获取所在cell

    [cell.btn addTarget:self action:@selector(cellBtnClicked:event:) forControlEvents:UIControlEventTouc ...

  4. MySQL 主从同步

    http://blog.csdn.net/z69183787/article/details/53897894

  5. Generic Access Profile

    转自:https://www.bluetooth.com/specifications/assigned-numbers/generic-access-profile ​​Assigned numbe ...

  6. JavaScript Canvas 根据像素点取位置

    <html> <body> <canvas id="canvas" width="100" height="100&qu ...

  7. Delphi管理多线程之线程局部存储:threadvar

    尽管多线程能够解决许多问题,但是同时它又给我们带来了很多的问题.其中主要的问题就是:对全局变量或句柄这样的全局资源如何访问?另外,当必须确保一个线程中的某些事件要在另一个线程中的其他时间之前(或之后) ...

  8. 【翻译四】java-并发之线程暂停

    Pausing Execution with Sleep Thread.sleep causes the current thread to suspend execution for a speci ...

  9. 【JAVA与XML、dtd约束、Schema约束】

    一.XML. (1)XML:Extensible Markup Language (2)XML是一种标记语言. (3)XML的设计宗旨是传输数据,而不是显示数据. (4)XML标签没有被预定义,即使用 ...

  10. 攻城狮在路上(壹) Hibernate(十)--- 映射值类型集合

    一.映射Set(集):未排序,无重复. 实例代码: <set name="images" table="IMAGES" lazy="true&q ...