POJ1915Knight Moves（单向BFS + 双向BFS）

题目链接

单向bfs就是水题

 #include <iostream>
 #include <cstring>
 #include <cstdio>
 #include <algorithm>
 #include <queue>
 using namespace std;
 const int INF = 0x3f3f3f3f;
 const int Max =  + ;
 struct Node
 {
     int x, y;
 };
 int g[Max][Max];
 int vis[Max][Max];
 int n, sx, sy, ex, ey;
 int gx[] = {-, -, -, -, , , , };
 int gy[] = {-, -, , , , , -, -};
 bool in_bound(int x, int y)
 {
     if (x >=  && y >=  && x < n && y < n)
         return true;
     return false;
 }
 int bfs(int sx, int sy)
 {
     Node node, temp;
     node.x = sx;
     node.y = sy;
     vis[sx][sy] = ;
     queue<Node> q;
     q.push(node);
     while (!q.empty())
     {
         node = q.front();
         q.pop();
         if (node.x == ex && node.y == ey)
             return vis[ex][ey];
         for (int i = ; i < ; i++)
         {
             int fx = node.x + gx[i];
             int fy = node.y + gy[i];
             if (in_bound(fx, fy) && vis[fx][fy] > vis[node.x][node.y] + )
             {
                 temp.x = fx;
                 temp.y = fy;
                 vis[fx][fy] = vis[node.x][node.y] + ;
                 q.push(temp);
             }
         }
     }
     return -;
 }
 int main()
 {
     int test;
     scanf("%d", &test);
     while (test--)
     {
         scanf("%d", &n);
         scanf("%d%d%d%d", &sx, &sy, &ex, &ey);
         memset(vis, INF, sizeof(vis));
         printf("%d\n", bfs(sx, sy));
     }
     return ;
 }

单向bfs

做这题主要是学着写双向bfs；

分别从起点和终点开始搜，如果重合即找到

从这个博客学会的

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
using namespace std;
const int INF = 0x3f3f3f3f;
const int Max =  + ;
struct Node
{
    int x, y;
    bool step;
};
// 这个step的意思之前没搞明白，他其实就是指的 在某一步下可以走到点
//开始讲 start.step设为true,因此在只能走一次 8 个点，然后8个点都是第一步走的，然后把最后一个点的step设为true,当你走第二部时候，就是 do { 以这个点扩展 8 步} while ( !current.step) step控制了层数。
int g[Max][Max];
int vis[Max][Max];
int n, sx, sy, ex, ey;
int gx[] = {-, -, -, -, , , , };
int gy[] = {-, -, , , , , -, -};
bool in_bound(int x, int y)
{
    if (x >=  && y >=  && x < n && y < n)
        return true;
    return false;
}
int bfs()
{
    if (sx == ex && sy == ey)
        return ;
    Node start, finish;
    start.x = sx;
    start.y = sy;
    start.step = true;
    finish.x = ex;
    finish.y = ey;
    finish.step = true;
    vis[sx][sy] = ;
    vis[ex][ey] = ;
    queue<Node> frontSearch;
    queue<Node> backSearch;
    int fstep = , bstep = ;
    frontSearch.push(start);
    backSearch.push(finish);
    Node current;
    while (!frontSearch.empty() || !backSearch.empty())
    {
        if (!frontSearch.empty())
        {
            do
            {
                current = frontSearch.front();
                frontSearch.pop();
                for (int i = ; i < ; i++)
                {
                    int fx = current.x + gx[i];
                    int fy = current.y + gy[i];
                    if (in_bound(fx, fy))
                    {
                        if (vis[fx][fy] == )
                        {
                            return fstep + bstep + ;
                        }
                        if (!vis[fx][fy])
                        {
                            vis[fx][fy] = ;
                            Node temp;
                            temp.x = fx;
                            temp.y = fy;
                            temp.step = false;
                            frontSearch.push(temp);
                        }
                    }
                }
            }while(current.step == false);
            fstep++;
            current = frontSearch.front();
            frontSearch.pop();
            current.step = true;  // 为了让最后队列中最后一个数step为true，先将队首拿出来，修改step,然后在入队
            frontSearch.push(current);
        }

        if (!backSearch.empty())
        {
            do
            {
                current = backSearch.front();
                backSearch.pop();
                for (int i = ; i < ; i++)
                {
                    int fx = current.x + gx[i];
                    int fy = current.y + gy[i];
                    if (in_bound(fx, fy))
                    {
                        if (vis[fx][fy] == )
                        {
                            return bstep + fstep + ;
                        }
                        if (!vis[fx][fy])
                        {
                            vis[fx][fy] = ;
                            Node temp;
                            temp.x = fx;
                            temp.y = fy;
                            temp.step = false;
                            backSearch.push(temp);
                        }
                    }
                }
            } while(current.step == false);
            bstep++;
            current = backSearch.front();
            backSearch.pop();
            current.step = true;
            backSearch.push(current);
        }
    }
    return -;
}
int main()
{
    int test;
    scanf("%d", &test);
    while (test--)
    {
        scanf("%d", &n);
        scanf("%d%d%d%d", &sx, &sy, &ex, &ey);
        memset(vis, , sizeof(vis));
        printf("%d\n", bfs());
    }
    return ;
}

第二种 双向bfs写法：

 #include <iostream>
 #include <cstring>
 #include <cstdio>
 #include <algorithm>
 #include <queue>
 using namespace std;
 const int INF = 0x3f3f3f3f;
 const int Max =  + ;
 struct Node
 {
     int x, y;
     bool step;
 };
 int g[Max][Max];
 int fvis[Max][Max], bvis[Max][Max];
 int n, sx, sy, ex, ey;
 int gx[] = {-, -, -, -, , , , };
 int gy[] = {-, -, , , , , -, -};
 bool in_bound(int x, int y)
 {
     if (x >=  && y >=  && x < n && y < n)
         return true;
     return false;
 }
 int bfs()
 {
     if (sx == ex && sy == ey)
         return ;
     Node start, finish;
     start.x = sx;
     start.y = sy;
     start.step = true;
     finish.x = ex;
     finish.y = ey;
     finish.step = true;
     fvis[sx][sy] = ;
     bvis[ex][ey] = ;
     queue<Node> frontSearch;
     queue<Node> backSearch;
     int fstep = , bstep = ;
     frontSearch.push(start);
     backSearch.push(finish);
     Node current;
     while (!frontSearch.empty() || !backSearch.empty())
     {
         int frontSize = (int) frontSearch.size();
         while (frontSize--)  // 直接将这一个队 全都 拿出来更新，就相当于上一中的step一样，控制搜索的层次
         {
             current = frontSearch.front();
             frontSearch.pop();

             for (int i = ; i < ; i++)
             {
                 int fx = current.x + gx[i];
                 int fy = current.y + gy[i];
                 if (in_bound(fx, fy))
                 {
                     if (bvis[fx][fy] != -)  // 如果 倒着搜 已经搜到了，返回
                         return fvis[current.x][current.y] +  + bvis[fx][fy];
                     if (fvis[fx][fy] == -) //否则正着+1
                     {
                         Node temp;
                         temp.x = fx;
                         temp.y = fy;
                         fvis[fx][fy] = fvis[current.x][current.y] + ;
                         frontSearch.push(temp);
                     }
                 }
             }
         }
         int backSize = (int) backSearch.size();
         while (backSize--)
         {
             current = backSearch.front();
             backSearch.pop();

             for (int i = ; i < ; i++)
             {
                 int fx = current.x + gx[i];
                 int fy = current.y + gy[i];
                 if (in_bound(fx, fy))
                 {
                     if (fvis[fx][fy] != -)
                     {
                         return bvis[current.x][current.y] +  + fvis[fx][fy];
                     }
                     if (bvis[fx][fy] == -)
                     {
                         Node temp;
                         temp.x = fx;
                         temp.y = fy;
                         bvis[fx][fy] = bvis[current.x][current.y] + ;
                         backSearch.push(temp);
                     }
                 }
             }
         }
     }
     return -;
 }
 int main()
 {
     int test;
     scanf("%d", &test);
     while (test--)
     {
         scanf("%d", &n);
         scanf("%d%d%d%d", &sx, &sy, &ex, &ey);
         memset(fvis, -, sizeof(fvis));
         memset(bvis, -, sizeof(bvis));
         printf("%d\n", bfs());
     }
     return ;
 }

双向bfs 方法二