Beautiful Number


Time Limit: 2 Seconds      Memory Limit: 65536 KB

Mike is very lucky, as he has two beautiful numbers, 3 and 5. But he is so greedy that he wants infinite beautiful numbers. So he declares that any positive number which is dividable by 3 or 5 is beautiful number. Given you an integer N (1 <= N <= 100000), could you please tell mike the Nth beautiful number?

Input

The input consists of one or more test cases. For each test case, there is a single line containing an integer N.

Output

For each test case in the input, output the result on a line by itself.

Sample Input

1
2
3
4

Sample Output

3
5
6
9

 #include <iostream>
#include <vector>
#include <cstdio>
using namespace std;
vector<int> v;
int main(){
int n = , i = , num;
while(){
if(n > )
break;
if(i % == || i % == ){
v.push_back(i);
n++;
}
i++;
}
while(cin >> num){
printf("%d\n", v[num - ]);
}
return ;
}

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