CF-478C
You have r red, g green and b blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number t of tables can be decorated if we know number of balloons of each color?
Your task is to write a program that for given values r, g and b will find the maximum number t of tables, that can be decorated in the required manner.
The single line contains three integers r, g and b (0 ≤ r, g, b ≤ 2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space.
Print a single integer t — the maximum number of tables that can be decorated in the required manner.
5 4 3
4
1 1 1
1
2 3 3
2
In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively.
分析:
1.首先排序,
2.如果前两者之和的两倍小于第三者。那么个数就是前两者之和的个数
3.如果前两者之和的两倍大于第三者。我们可以这么想,先用第三者与前两者2:1平衡掉,然后前两者2:1一直走。也就是总数除以三
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int main()
{
long long a[];
scanf("%lld%lld%lld",&a[],&a[],&a[]);
sort(a,a+);
if((a[]+a[])*<=a[])
{
printf("%d\n",a[]+a[]);
}
else
{
printf("%d\n",(a[]+a[]+a[])/);
}
}
CF-478C的更多相关文章
- ORA-00494: enqueue [CF] held for too long (more than 900 seconds) by 'inst 1, osid 5166'
凌晨收到同事电话,反馈应用程序访问Oracle数据库时报错,当时现场现象确认: 1. 应用程序访问不了数据库,使用SQL Developer测试发现访问不了数据库.报ORA-12570 TNS:pac ...
- cf之路,1,Codeforces Round #345 (Div. 2)
cf之路,1,Codeforces Round #345 (Div. 2) ps:昨天第一次参加cf比赛,比赛之前为了熟悉下cf比赛题目的难度.所以做了round#345连试试水的深浅..... ...
- cf Round 613
A.Peter and Snow Blower(计算几何) 给定一个点和一个多边形,求出这个多边形绕这个点旋转一圈后形成的面积.保证这个点不在多边形内. 画个图能明白 这个图形是一个圆环,那么就是这个 ...
- ARC下OC对象和CF对象之间的桥接(bridge)
在开发iOS应用程序时我们有时会用到Core Foundation对象简称CF,例如Core Graphics.Core Text,并且我们可能需要将CF对象和OC对象进行互相转化,我们知道,ARC环 ...
- [Recommendation System] 推荐系统之协同过滤(CF)算法详解和实现
1 集体智慧和协同过滤 1.1 什么是集体智慧(社会计算)? 集体智慧 (Collective Intelligence) 并不是 Web2.0 时代特有的,只是在 Web2.0 时代,大家在 Web ...
- CF memsql Start[c]UP 2.0 A
CF memsql Start[c]UP 2.0 A A. Golden System time limit per test 1 second memory limit per test 256 m ...
- CF memsql Start[c]UP 2.0 B
CF memsql Start[c]UP 2.0 B B. Distributed Join time limit per test 1 second memory limit per test 25 ...
- CF #376 (Div. 2) C. dfs
1.CF #376 (Div. 2) C. Socks dfs 2.题意:给袜子上色,使n天左右脚袜子都同样颜色. 3.总结:一开始用链表存图,一直TLE test 6 (1)如果需 ...
- CF #375 (Div. 2) D. bfs
1.CF #375 (Div. 2) D. Lakes in Berland 2.总结:麻烦的bfs,但其实很水.. 3.题意:n*m的陆地与水泽,水泽在边界表示连通海洋.最后要剩k个湖,总要填掉多 ...
- CF #374 (Div. 2) D. 贪心,优先队列或set
1.CF #374 (Div. 2) D. Maxim and Array 2.总结:按绝对值最小贪心下去即可 3.题意:对n个数进行+x或-x的k次操作,要使操作之后的n个数乘积最小. (1)优 ...
随机推荐
- 洛谷 - P1433 - 吃奶酪 - dfs
https://www.luogu.org/problemnew/show/P1433 并不是每一个求最短距离就是bfs,这个肯定是dfs. 直接计算15!可以知道枚举必定超时,但是! 我们dfs非常 ...
- Linux 问题 卸载setup.py方式安装的python包
python ./setup.py install --record install.txt cat install.txt | xargs rm -rf
- python string类型 bytes类型 bytearray类型
一.python3对文本和二进制数据做了区分.文本是Unicode编码,str类型,用于显示.二进制类型是bytes类型,用于存储和传输.bytes是byte的序列,而str是unicode的序列. ...
- java实训 :异常(try-catch执行顺序与自定义异常)
关键字: try:执行可能产生异常的代码 catch:捕获异常 finally:无论是否发生异常代码总能执行 throws:声明方法可能要抛出的各种异常 throw:手动抛出自定义异常 用 try-c ...
- iOS 获取当前响应链的First Responder (Swift)
import UIKit private weak var currentFirstResponder: AnyObject? extension UIResponder { static func ...
- Pursuit For Artifacts CodeForces - 652E
https://vjudge.net/problem/CodeForces-652E 边双啊,就是点双那个tarjan里面,如果low[v]==dfn[v](等同于low[v]>dfn[u]), ...
- DFS/并查集 Codeforces Round #286 (Div. 2) B - Mr. Kitayuta's Colorful Graph
题目传送门 /* 题意:两点之间有不同颜色的线连通,问两点间单一颜色连通的路径有几条 DFS:暴力每个颜色,以u走到v为结束标志,累加条数 注意:无向图 */ #include <cstdio& ...
- magento package
Magento Local module file is relative to app/code/local/ Magento Community module file is relative t ...
- 记录两个python itchat的用法博客网址
http://www.tuicool.com/articles/VJZRRfn https://itchat.readthedocs.io/zh/latest/
- Solr打分排序规则自定义【转】
在搭建好solrCloud搜索集群后,通过编写基本的查询显示语句已经能够通过输入关键字查询到相应结果进行显示,但是在显示结果排序上以及不相关信息过滤问题上,如何制定合理的打分规则得到理想的结果集确实比 ...