CF-796B
B. Find The Bonetime limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
Zane the wizard is going to perform a magic show shuffling the cups.
There are n cups, numbered from 1 to n, placed along the x-axis on a table that has m holes on it. More precisely, cup i is on the table at the position x = i.
The problematic bone is initially at the position x = 1. Zane will confuse the audience by swapping the cups k times, the i-th time of which involves the cups at the positions x = ui and x = vi. If the bone happens to be at the position where there is a hole at any time, it will fall into the hole onto the ground and will not be affected by future swapping operations.
Do not forget that Zane is a wizard. When he swaps the cups, he does not move them ordinarily. Instead, he teleports the cups (along with the bone, if it is inside) to the intended positions. Therefore, for example, when he swaps the cup at x = 4 and the one at x = 6, they will not be at the position x = 5 at any moment during the operation.
Zane’s puppy, Inzane, is in trouble. Zane is away on his vacation, and Inzane cannot find his beloved bone, as it would be too exhausting to try opening all the cups. Inzane knows that the Codeforces community has successfully helped Zane, so he wants to see if it could help him solve his problem too. Help Inzane determine the final position of the bone.
InputThe first line contains three integers n, m, and k (2 ≤ n ≤ 106, 1 ≤ m ≤ n, 1 ≤ k ≤ 3·105) — the number of cups, the number of holes on the table, and the number of swapping operations, respectively.
The second line contains m distinct integers h1, h2, ..., hm (1 ≤ hi ≤ n) — the positions along the x-axis where there is a hole on the table.
Each of the next k lines contains two integers ui and vi (1 ≤ ui, vi ≤ n, ui ≠ vi) — the positions of the cups to be swapped.
OutputPrint one integer — the final position along the x-axis of the bone.
Examplesinput7 3 4
3 4 6
1 2
2 5
5 7
7 1output1input5 1 2
2
1 2
2 4output2NoteIn the first sample, after the operations, the bone becomes at x = 2, x = 5, x = 7, and x = 1, respectively.
In the second sample, after the first operation, the bone becomes at x = 2, and falls into the hole onto the ground.
题意:
有n个杯子,m个杯子底下有洞,将骨头交换k次,遇到洞就会掉下去不动,求最后骨头的位置。
注意交换的两个位置是不分先后的。
AC代码:
#include<bits/stdc++.h>
using namespace std; int main(){
ios::sync_with_stdio(false);
int h[];
int n,m,k,t,s,flag=,ans=;
cin>>n>>m>>k;
//scanf("%d%d%d",&n,&m,&k);
memset(h,,sizeof(h));
for(int i=;i<m;i++){
cin>>t;
//scanf("%d",&t);
h[t]=;
}
if(h[]){
flag=;
}
for(int i=;i<k;i++){
cin>>t>>s;
//scanf("%d%d",&t,&s);
if(!h[t]&&ans==t){
ans=s;
}
else if(!h[s]&&ans==s){
ans=t;
}
}
cout<<ans<<endl;
return ;
}
CF-796B的更多相关文章
- ORA-00494: enqueue [CF] held for too long (more than 900 seconds) by 'inst 1, osid 5166'
凌晨收到同事电话,反馈应用程序访问Oracle数据库时报错,当时现场现象确认: 1. 应用程序访问不了数据库,使用SQL Developer测试发现访问不了数据库.报ORA-12570 TNS:pac ...
- cf之路,1,Codeforces Round #345 (Div. 2)
cf之路,1,Codeforces Round #345 (Div. 2) ps:昨天第一次参加cf比赛,比赛之前为了熟悉下cf比赛题目的难度.所以做了round#345连试试水的深浅..... ...
- cf Round 613
A.Peter and Snow Blower(计算几何) 给定一个点和一个多边形,求出这个多边形绕这个点旋转一圈后形成的面积.保证这个点不在多边形内. 画个图能明白 这个图形是一个圆环,那么就是这个 ...
- ARC下OC对象和CF对象之间的桥接(bridge)
在开发iOS应用程序时我们有时会用到Core Foundation对象简称CF,例如Core Graphics.Core Text,并且我们可能需要将CF对象和OC对象进行互相转化,我们知道,ARC环 ...
- [Recommendation System] 推荐系统之协同过滤(CF)算法详解和实现
1 集体智慧和协同过滤 1.1 什么是集体智慧(社会计算)? 集体智慧 (Collective Intelligence) 并不是 Web2.0 时代特有的,只是在 Web2.0 时代,大家在 Web ...
- CF memsql Start[c]UP 2.0 A
CF memsql Start[c]UP 2.0 A A. Golden System time limit per test 1 second memory limit per test 256 m ...
- CF memsql Start[c]UP 2.0 B
CF memsql Start[c]UP 2.0 B B. Distributed Join time limit per test 1 second memory limit per test 25 ...
- CF #376 (Div. 2) C. dfs
1.CF #376 (Div. 2) C. Socks dfs 2.题意:给袜子上色,使n天左右脚袜子都同样颜色. 3.总结:一开始用链表存图,一直TLE test 6 (1)如果需 ...
- CF #375 (Div. 2) D. bfs
1.CF #375 (Div. 2) D. Lakes in Berland 2.总结:麻烦的bfs,但其实很水.. 3.题意:n*m的陆地与水泽,水泽在边界表示连通海洋.最后要剩k个湖,总要填掉多 ...
- CF #374 (Div. 2) D. 贪心,优先队列或set
1.CF #374 (Div. 2) D. Maxim and Array 2.总结:按绝对值最小贪心下去即可 3.题意:对n个数进行+x或-x的k次操作,要使操作之后的n个数乘积最小. (1)优 ...
随机推荐
- 新建 .NET Core 控制台项目 C# 数组深拷贝
新建 .NET Core 控制台项目 1. 安装 .NET Core SDK 1.0 参考微软官方网站 https://www.microsoft.com/net/download/windows 2 ...
- 《好好说话》zz
最近,<奇葩说>闹出来了一些不愉快. 在半决赛中,姜思达惜败,愤怒的粉丝把矛头指向那场比赛的其他人.最终,马薇薇.黄执中和网友们吵起来了. 这件事本不算大事,毕竟娱乐业就是这个样子.刚刚好 ...
- erlang防止反编译
前面提到了erlang的反编译,下面说下防止反编译: 1)建立~/.erlang.crypt 在编译的用户名的home目录中建立一个加密方法的文件.erlang.crypt,内容如下: [{debug ...
- 51 NOD 1753 相似子串 字符串hash
1735 相似子串 基准时间限制:5 秒 空间限制:131072 KB 分值: 80 两个字符串相似定义为:1.两个字符串长度相等2.两个字符串对应位置上有且仅有至多一个位置所对应的字符不 ...
- 基于live555实现的跨平台高性能RTSPServer流媒体服务器EasyIPCamera
本文转自EasyDarwin团队成员kim的博客:http://blog.csdn.net/jinlong0603/article/details/52366412 简介 EasyIPCamera是由 ...
- NET 并发编程
场景并发调用API 1.简单封装httpclient public class CommonHelper { private static readonly HttpClient _httpClien ...
- C++笔记之用户定义的转换
用户定义的转换(User-defined Conversion) 是一种将一个类类型转换为另一种类型的机制 语法 operator conversion-type-idexplicit operato ...
- Win10更新后,IE和Edge以外的浏览器打开网页速度慢的解决方案
下载修复工具,提取码:you0 以管理员身份运行修复工具,点击“修复” 点击“确定” 提示“修复成功” 参考链接:Win10下极速模式无法打开网页的解决办法_360社区
- MQ发送的消息都到了死信队列中了
MQ在发送消息的时候,设置的过期时间太短.(昨天项目上线遇到了,开发中也遇到一次.)谨记!!!
- Protocol_BGP
BGP协议 作者:Danbo 2015-7-8 BPG最重要的就是属性,下面我们针对路径属性分析一下.
