Problem 1008 Hay Points
Problem Description
Each employee of a bureaucracy has a job description - a few paragraphs that describe the responsibilities of the job. The employee's job description, combined with other factors, such as seniority, is used to determine his or her salary.
The Hay Point system frees the Human Resources department from having to make an intelligent judgement as to the value of the employee; the job description is merely scanned for words and phrases that indicate responsibility. In particular, job descriptions that indicate control over a large budget or management over a large number of people yield high Hay Point scores.
You are to implement a simplified Hay Point system. You will be given a Hay Point dictionary and a number of job descriptions. For each job description you are to compute the salary associated with the job, according to the system.
The first line of input contains 2 positive integers: m <= 1000, the number of words in the Hay Point dictionary, and n <= 100, the number of job descriptions. m lines follow; each contains a word (a string of up to 16 lower-case letters) and a dollar value (a real number between 0 and 1,000,000). Following the dictionary are the n job descriptions. Each job description consists of one or more lines of text; for your convenience the text has been converted to lower case and has no characters other than letters, numbers, and spaces. Each job description is terminated by a line containing a period.
For each job description, output the corresponding salary computed as the sum of the Hay Point values for all words that appear in the description. Words that do not appear in the dictionary have a value of 0.
Sample Input
Sample Output
{
{
;i<=n;i++)
cin>>k[i].s>>k[i].p;
sum=;
;i<=m;i++)
{
{
;j<=n;j++)
sum+=k[j].p;
}
cout <<sum<<endl;
sum=;
}
}
;
}
Problem 1008 Hay Points的更多相关文章
- Hay Points
Hay Points TimeLimit: 1 Second MemoryLimit: 32 Megabyte Totalsubmit: 1022 Accepted: 602 Descript ...
- Problem : 1008 ( Elevator )
好操蛋啊,电梯竟然能原地不动,你大爷的,这逻辑,太弱智了.... Problem : 1008 ( Elevator ) Judge Status : Accepted RunId : 103 ...
- POJ 2403 Hay Points
Hay Points Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5735 Accepted: 3695 Descri ...
- 题解西电OJ (Problem 1008 - 数星星)
题目内容: Description “不要问我太阳有多高 我会告诉你我有多真 不要问我星星有几颗 我会告诉你很多很多” 一天Qinz和wudired在天上数星星,由于星星可以排列成一条直线,他们比赛看 ...
- HDU contest808 ACM多校第7场 Problem - 1008: Traffic Network in Numazu
首先嘚瑟一下这场比赛的排名:59 (第一次看到这么多 √ emmmm) 好了进入正文QAQ ...这道题啊,思路很清晰啊. 首先你看到树上路径边权和,然后还带修改,不是显然可以想到 树剖+线段树 维护 ...
- 【线段树】Petrozavodsk Summer Training Camp 2016 Day 6: Warsaw U Contest, XVI Open Cup Onsite, Sunday, August 28, 2016 Problem H. Hay
有一些草,一开始高度都是0,它们的生长速率不同. 给你一些单增的日期,在这些日期要将>b的草的部分都割掉,问你每次割掉的部分有多少. 将草的生长速率从大到小排序,这样每次割掉的是一个后缀,而且不 ...
- AtCoder Grand Contest 025 Problem D - Choosing Points
题目大意:输入$n,d1,d2$,你要找到$n^2$个整点 x, y 满足$0 \leqslant x, y<2n$.并且找到的任意两个点距离,既不是$\sqrt{d1}$,也不是 $\sqrt ...
- Poj 2403 Hay Points(Map)
一.题目大意 实现一个工资计算系统.工资的计算规则是:首先,给定一些关键字和对应的价值,这个相对于字典.然后给出的是求职者的描述,如果这个描述中包含关键字则加上对应的价值,总得价值就是这个求职者的工资 ...
- UVa 10295 - Hay Points
题目:有非常多工人.相应一个能力描写叙述表,每种能力有一个权值,求每一个工人的能力值. 分析:字符串.hash表,字典树.利用散列表或者字典树存储相应的单词和权值.查询就可以. 说明:注意初始化,计算 ...
随机推荐
- [C++程序设计]用指向数组的指针作函数参数
#include <iostream> using namespace std; int main() { ]); ][]={,,,,,,,,,,,}; output(a); ; } ]) ...
- centos搭建zabbix
安装一些依赖包,不同情况缺的包不同 yum install mysql-devel curl curl-devel net-snmp net-snmp-devel perl-DBI php-gd ph ...
- archlinux相关资料整理
Arch linux Arch Linux Wiki Arch linux Wiki Markdown Arch Wiki python continuing ...
- 百度地图JavaScript API V1.5初级开发工具类
/** * 百度地图使用工具类-v1.5 * @author boonya * @date 2013-7-7 * @address Chengdu,Sichuan,China * @email boo ...
- UESTC_神秘绑架案 CDOJ 881
神秘绑架案 Time Limit: 3000/1000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Others) Submit Sta ...
- Min Stack 解答
Question Design a stack that supports push, pop, top, and retrieving the minimum element in constant ...
- Light OJ 1067 Combinations (乘法逆元)
Description Given n different objects, you want to take k of them. How many ways to can do it? For e ...
- 过程化开发2048智力游戏WebApp
时间荏苒,唯编程与青春不可辜负,感觉自己一直没有专心去提升编程的技能,甚是惭愧!!! 周五,无意间看到一个开发2048的视频,有点兴趣就动起手来了,虽然不擅长前端开发,在此献丑,分享一下自己使用过程化 ...
- 求高精度幂(java)
求高精度幂 时间限制:3000 ms | 内存限制:65535 KB 难度:2 描述 对数值很大.精度很高的数进行高精度计算是一类十分常见的问题.比如,对国债进行计算就是属于这类问题. 现在要 ...
- 点击返回键退出popupwindow的方法
点击返回键退出popupwindow mPopupWindow.setFocusable(true); 这句非常重要,对背景不会有影响 mPopupWindow.setBackgroundDrawab ...