C++多线程之互斥锁和超时锁

#include<iostream>

#include<thread>

#include<mutex>

using namespace std;

mutex mu;

void ThreadSource(int i)

{

        mu.lock();

        cout << "线程" << i << "开始执行了" << endl;

        std::this_thread::sleep_for(1s);

        mu.unlock();

        std::this_thread::sleep_for(3ms); //如果不加延时可能会造成线程资源来不及释放

}

int main(int argc,char* argv[])

{

               

        for (int i = 0; i < 10; i++)

        {

               std::thread th(ThreadSource,i+1);

               th.detach();

        }

        

        getchar();

        return 0;

}

 

 

 

 

超时锁

#include<iostream>

#include<thread>

#include<mutex>

using namespace std;

timed_mutex mu;

void ThreadSource(int i)

{

        for (;;)

        {

               if (!mu.try_lock_for(chrono::milliseconds(500ms)))

               {

                       //如果未在规定时间内拿到锁，那么这段代码可能会出现问题，这里可以进行日志的写入，便于调试

                       cout << "线程"<<i<<"超时"<<endl;

               }

               cout << "线程" << i << "开始执行了" << endl;

               std::this_thread::sleep_for(1s);

               mu.unlock();

               std::this_thread::sleep_for(3ms); //如果不加延时可能会造成线程资源来不及释放

        }

}

int main(int argc,char* argv[])

{

               

        for (int i = 0; i < 10; i++)

        {

               std::thread th(ThreadSource,i+1);

               th.detach();

        }

        

        getchar();

        return 0;

}