ural 1113,jeep problem

题目链接：http://acm.timus.ru/problem.aspx?space=1&num=1113

网上的解答铺天盖地。我硬是花了两天才懂了点。

wiki上的解释：https://en.wikipedia.org/wiki/Jeep_problem

解答：每个点的油量是500,500*2,500*3... ...

每次的距离是500，500/3，500/5，... ...，500/2n-1;

#include <bits/stdc++.h>
using namespace std;

int main()
{
    double dist, tank;
    scanf("%lf%lf", &dist, &tank);
    double now = dist, cost = , pre;
    int k = ;
    while( (pre = now - tank / (*k-)) > ){
        cost += tank;
        now = pre;
        k++;
    }
    cost += now * (*k-);
    printf("%.0f\n", ceil(cost));
    return ;
}