HDu 1001 Sum Problem 分类： ACM 2015-06-19 23:38 12人阅读 评论(0) 收藏

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 338086    Accepted Submission(s): 85117

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).



In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

 

Input

The input will consist of a series of integers n, one integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

 

Sample Input

1
100

 

Sample Output

1

5050

 

Author

DOOM III

 

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这题其实没有想象的那么简单，要注意先除后乘这样不会爆掉，所以还要考虑奇偶，不过还有种办法是用double存，最后强转回int 也可以



#include<queue>

#include<math.h>

#include<stdio.h>

#include<string.h>

#include<iostream>

#include<algorithm>

using namespace std;

#define N 115





int main()

{

    int n;

    __int64 w;

    while(~scanf("%d",&n))

    {

        if(n%2==0) w=n/2*(n+1);

        else w=(n+1)/2*n;

        printf("%I64d\n\n",w);

    }









    return 0;

}

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