Words from cubes

Time Limit: Unknown ms
Memory Limit: 65536KB

This problem will be judged on CodeForcesGym. Original ID: 100735H
64-bit integer IO format: %I64d      Java class name: (Any)

 

Informikas was cleaning his drawers while he found a toy of his childhood. Well, it's not just a toy, it's a bunch of cubes with letters and digits written on them.

Informikas remembers that he could have make any word he could think of using these cubes. He is not sure about that now, because some of the cubes have been lost.

Informikas has already come up with a word he would like to make. Could you help him by saying if the word can be built from the cubes in the drawer?

 

Input

On the first line of input there is a string S, consisting of lowercase English letters, and an integer N (4 ≤ |S| ≤ 20, 1 ≤ N ≤ 100) – the word Informikas want to build and the number of cubes. On the every of the following N lines there are 6 characters. Every of those characters is either a lowercase English letter or a digit.

It is guaranteed that the string S consists only of lowercase English letters.

 

Output

Output one word, either "YES", if the word can be built using given cubes, or "NO" otherwise.

 

Sample Input

Input
dogs 4
d 1 w e 7 9
o 2 h a v e
g 3 c o o k
s 3 i e s 5
Output
YES
Input
banana 6
b a 7 8 9 1
n 1 7 7 7 6
a 9 6 3 7 8
n 8 2 4 7 9
a 7 8 9 1 3
s 7 1 1 2 7
Output
NO

Source

 
解题:最大匹配,匈牙利算法
 
 #include <bits/stdc++.h>
using namespace std;
const int maxn = ;
char str[maxn];
int n,Link[maxn];
bool w[maxn][maxn],used[maxn];
bool match(int u){
for(int i = ; i < n; ++i){
if(used[i] || !w[u][i]) continue;
used[i] = true;
if(Link[i] == - || match(Link[i])){
Link[i] = u;
return true;
}
}
return false;
}
int main(){
while(~scanf("%s",str)){
scanf("%d",&n);
memset(w,false,sizeof w);
char tmp[];
for(int i = ; i < n; ++i){
for(int j = ; j < ; ++j){
scanf("%s",tmp);
for(int k = ; str[k]; ++k)
if(str[k] == tmp[]) w[k][i] = true;
}
}
memset(Link,-,sizeof Link);
int ret = ;
for(int i = ; i < ; ++i){
memset(used,false,sizeof used);
if(match(i)) ++ret;
}
printf("%s\n",strlen(str) == ret?"YES":"NO");
}
return ;
}

CodeForcesGym 100735H Words from cubes的更多相关文章

  1. 水泡动画模拟(Marching Cubes)

    Marching Cubes算法是三维离散数据场中提取等值面的经典算法,其主要应用于医学领域的可视化场景,例如CT扫描和MRI扫描的3D重建等. 算法主要的思想是在三维离散数据场中通过线性插值来逼近等 ...

  2. Codeforces525E Anya and Cubes(双向搜索)

    题目 Source http://codeforces.com/contest/525/problem/E Description Anya loves to fold and stick. Toda ...

  3. [saiku] 系统登录成功后查询Cubes

    一.系统启动时初始化ds和conn 1.查询出目前系统拥有的Datasources和Connections放入内存中 2.比对saiku-datasources中的ds是否有新增的,如果有,创建新的d ...

  4. UVa 10601 (Polya计数 等价类计数) Cubes

    用6种颜色去染正方体的12条棱,但是每种颜色都都限制了使用次数. 要确定正方体的每一条棱,可以先选择6个面之一作为顶面,然后剩下的四个面选一个作为前面,共有24种. 所以正方体的置换群共有24个置换. ...

  5. poj 1543 Perfect Cubes(注意剪枝)

    Perfect Cubes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14901   Accepted: 7804 De ...

  6. OpenJudge 2810(1543) 完美立方 / Poj 1543 Perfect Cubes

    1.链接地址: http://bailian.openjudge.cn/practice/2810/ http://bailian.openjudge.cn/practice/1543/ http:/ ...

  7. 组合数学(Pólya计数原理):UvaOJ 10601 Cubes

    Cubes You are given 12 rods of equal length. Each of them is colored in certain color. Your task is ...

  8. cf492A Vanya and Cubes

    A. Vanya and Cubes time limit per test 1 second memory limit per test 256 megabytes input standard i ...

  9. uva 10051 Tower of Cubes(DAG最长路)

    题目连接:10051 - Tower of Cubes 题目大意:有n个正方体,从序号1~n, 对应的每个立方体的6个面分别有它的颜色(用数字给出),现在想要将立方体堆成塔,并且上面的立方体的序号要小 ...

随机推荐

  1. POJ Area of Simple Polygons 扫描线

    这个题lba等神犇说可以不用离散化,但是我就是要用. 题干: Description There are N, <= N <= , rectangles -D xy-plane. The ...

  2. Sort List 典型链表

    https://leetcode.com/problems/sort-list/ Sort a linked list in O(n log n) time using constant space ...

  3. PCB genesis孔符制作实现方法

    一.先看genesis原始孔符 孔符的作用:用于表示孔径的大小的一种代号, 当孔径检测时,可以按分孔图中的孔符对应的孔径尺寸对孔径检测. 在实际PCB行业通常不使用原始(图形)孔符,而使用字母孔符(如 ...

  4. codevs2503失恋28天......(背包dp)

    503 失恋28天-缝补礼物  时间限制: 1 s  空间限制: 32000 KB  题目等级 : 黄金 Gold   题目描述 Description 话说上回他给女孩送了n件礼物,由于是廉价的所以 ...

  5. Django day30 自定义配置settings文件,分页器,版本控制

    一:自定义配置settings文件 1.有两套配置文件,默认配置,用户的配置 2.如果某个字段,用户配置了,就用用户的,如果没配置,就用默认的 二:分页器 1.三种分页: # 普通分页 from re ...

  6. DataFrame入门案例(集团公司对人事信息处理场景)

    我用一个集团公司对人事信息处理场景的简单案例,来作为入门,详细分析DataFrame上的各种常用操作,包括集团子公司的职工人事信息的合并,职工的部门相关信息查询.职工信息的统计.关联职工与部门信息的统 ...

  7. C# 多线程系列(六)

    同步 当多个线程共享一些数据的时候,我们就需要使用同步技术,确保一次只有一个线程访问合改变共享状态.注意,同步问题与争用和死锁有关. 例: ; static void Add() { ; i < ...

  8. 前端h5开发调试神奇vconsole

    (1)项目中安装vconcole插件 npm install vconcole (2)在vue项目中main.js中引入插件 import Vconsole from 'vconsole'; cons ...

  9. Android studio & SDK的国内有效站点。

    SDK.TOOLS的国内有效镜像节点: mirrors.zzu.edu.cn/android/repository/ 网上的地址只写了mirrors.zzu.edu.cn,有误,需要补齐后面的子目录才 ...

  10. JS——设置cookie

    cookie 用来识别用户. <html> <head> <script type="text/javascript"> function ge ...