mysql语句实现年龄分布

1、mysql语句实现年龄分布
select nnd as '年龄段',count(*) as '人数' from(
 select
 case
  when age>= and age<= then '1-10'
  when age>= and age<= then '11-20'
  when age>= and age<= then '21-30'
  when age>= and age<= then '31-40'
  when age>= and age<= then '41-50'
  when age>= and age<= then '51-60'
  when age>= and age<= then '61-70'
  when age>= and age<= then '71-80'
  when age>= and age<= then '81-90'
  when age>= and age<= then '91-100'
 ELSE '无年龄' end
 as nnd from doc_info
)a group by nnd
2、查找病历中包含逗号的诊断数量
SELECT count(diag) FROM `doc_info_hive` where LOCATE(',',diag)>0  ;
3、查找病例中不包含逗号的诊断数量
SELECT count(diag) FROM `doc_info_hive` where LOCATE(',',diag)=0  ;