【423】COMP9024 Revision
目录:
1. array:
参考:C 数组
参考:C 字符串
总结:【个人理解,可能不全面】数组对于数字型和字符型有不同,数字数组就是实际长度,而字符型数组需要增加一个 '\0',所以对于数字数组可以这样定义 int num[] = {, , , , }; ,而字符型数组需要预先定义长度,否则没有 '\0' 会出错,需要这样定义 char str[6] = {'h', 'e', 'l', 'l', 'o'};或者 char str[] = "hello",会自动添加 '\0'。
#include <stdio.h>
#include <string.h> int main(void)
{
char *r = "hello";
char s[10] = {'h','e','l','l','o'};
char ss[] = {'h','e','l','l','o'};
char t[] = "hello"; int num[] = {1, 2, 3, 4, 5}; printf ("r = %s\ns = %s\nss = %s\nt = %s\n", r, s, ss, t);
printf ("The length of r is %ld.\n", sizeof(r)); // address
printf ("The strlen of r is %ld.\n", strlen(r)); // actual length
printf ("The length of s is %ld.\n", sizeof(s)); // s[10] with '\0'
printf ("The length of ss is %ld.\n", sizeof(ss)); // print with error
printf ("The length of t is %ld.\n", sizeof(t)); // t[6] with '\0'
printf ("The strlen of t is %ld.\n", strlen(t)); // actual length
printf ("The length of num is %ld.\n", sizeof(num)/sizeof(num[0])); // actual length for (int i = 0; i < sizeof(num)/sizeof(num[0]); i++) {
printf("%d\n", num[i]);
} /* r = hello*/
/* s = hello*/
/* ss = hellohello ----error----*/
/* t = hello*/
/* The length of r is 8.*/
/* The strlen of r is 5.*/
/* The length of s is 10.*/
/* The length of ss is 5. ----without '\0'----*/
/* The length of t is 6.*/
/* The strlen of t is 5.*/
/* The length of num is 5.*/
/* 1*/
/* 2*/
/* 3*/
/* 4*/
/* 5*/ return 0;
}
2. '\0' 与 EOF 的区别
前者作为字符串的结尾标志
后者作为文件的结尾标志
如下所示:(0,与 -1)
#include <stdio.h>
#include <stdlib.h> int main(){
printf("\'\\0\' is %d\n", '\0');
printf("EOF is %d\n", EOF); /* '\0' is 0*/
/* EOF is -1*/ return 0;
}
3. 二维字符数组(字符串数组)
多维字符数组可以用双星号来表示
参考:C语言的字符串数组
参考:指向指针的指针
#include <stdio.h>
#include <stdlib.h> int main(){
// str is the pointer of array which is still pointer
char *str[] = {"alex", "bn", "lee"}; // str[0] means the first array (e.g. "alex")
printf("The first string is %s.\n", str[0]);
// str + 1 means the pointer of second array
// add * in front of it, then it will become the pointer of chars
// and it can be printed as string
printf("The second string is %s.\n", *(str + 1));
// Just like above one
// *(str + 2) means the pointer of chars (e.g. "lee")
// *(str + 2) + 1 means the pointer of the second character
// *((str + 2) + 1) means element of that pointer
printf("The second character of the third string is %c.\n", *(*(str + 2) + 1)); /* outputs:*/
/* The first string is alex.*/
/* The second string is bn.*/
/* The second character of the third string is e.*/ return 0;
}
双星号:不能直接定义信息,需要指向
#include <stdio.h>
#include <stdlib.h> int main(){
// str is the pointer of array which is still pointer
char *str_o[] = {"alex", "bn", "lee"};
// you can't assignment **str directly since it can only be used for string (* to array)
// but you can define a **str point to str_o
char **str = str_o; // str[0] means the first array (e.g. "alex")
printf("The first string is %s.\n", *str);
// str + 1 means the pointer of second array
// add * in front of it, then it will become the pointer of chars
// and it can be printed as string
printf("The second string is %s.\n", *(str + 1));
// Just like above one
// *(str + 2) means the pointer of chars (e.g. "lee")
// *(str + 2) + 1 means the pointer of the second character
// *((str + 2) + 1) means element of that pointer
printf("The second character of the third string is %c.\n", *(*(str + 2) + 1)); /* outputs:*/
/* The first string is alex.*/
/* The second string is bn.*/
/* The second character of the third string is e.*/ return 0;
}
4. typedef & struct
struct 基本格式如下:(注意最后的 semicolon)
struct date {
int day;
int month;
int year;
};
// struct date will become one thing
struct date birthday;
typedef 可以将一个整体的东西用一个新的字符串表示
typedef struct {
int a;
int b;
} Pair;
...
Pair x;
or
typedef struct date Date
Date d;
struct 中的指针使用
// pointerstruct.c
#include <stdio.h> typedef struct {
int name;
int salary;
} Worker; // Worker is now a type, like char and int int main(void) {
Worker w, *wp; // define variables with the new type wp = &w;
*wp.salary = 125000; // generates a compiler error (see below)
*(wp.salary) = 125000; // so does this (same as previous line) w.salary = 125000; // is probably what you want
(*wp).salary = 125000; // or you can use the pointer, but this looks kludgy
wp->salary = 125000; // this is the 'sexy' way to use pointers return 0; // being lazy, should be EXIT_SUCCESS
}
简化如下:
structTypeName s, *sp;
sp = &s; // then the following are equivalent: s.element
(*sp).element
sp->element
5. Makefile
An example of a rule in a Makefile is:
ex1: ex1.c ex1.h
dcc -O3 -o ex1 ex1.c
It is important to note that dcc above is preceded by a tab (and not spaces).
Every file in UNIX has a timestamp, which is the time it was created or last modified.
If you type in the command make, then make will compare the timestamps of each of the files in the dependencies with the target.
If any of these dependency files is newer than the target, make will execute the command again (which usually makes the target again).
If none of the files is newer, make simply reports that the target is up to date.
You can have multiple targets. Below we show three targets:
all: ex1 ex2 ex1: ex1.c ex1.h
dcc -O3 -o ex1 ex1.c ex2: ex2.c ex2.h
dcc -O3 -o ex2 ex2.c
You can then type make ex1 or make ex2 as you wish.
If you type simply make, then the default is to make the first target only, which in this case is all, which in turn has as its dependencies the other two targets. This command will make either or both the executables if they are older than their course code.
You can generalise the Makefile by defining and using variables, such as:
CC=dcc
CFLAGS=-O3 all: ex1 ex2 ex1: ex1.c ex1.h
$(CC) $(CFLAGS) -o ex1 ex1.c ex2: ex2.c ex2.h
$(CC) $(CFLAGS) -o ex2 ex2.c
The variables will be substituted when the Makefile is executed.
You can also add a target to clean up your directory after you have finished:
CC=dcc
CFLAGS=-O3 all: ex1 ex2 ex1: ex1.c ex1.h
$(CC) $(CFLAGS) -o ex1 ex1.c ex2: ex2.c ex2.h
$(CC) $(CFLAGS) -o ex2 ex2.c clean:
rm -f ex1 ex2 ex1.o ex2.o core
the clean target has no dependencies, and here removes the executable, the object files, and core dumps
the command make clean will execute the rm instruction
the -f switch means that rm will not complain if any files are do not existent
6. 链表(Linked List)
typedef struct node {
int data;
struct node *next;
} LinkedL;
or
typedef struct node {
int data;
struct node *next;
} *LNode, *LinkedL;
列表遍历,可以通过 for 语句或者 while 语句,判别条件都是最后是否为 NULL
// traverse the list (of 2 elements)
for (LinkedL *p = n1; p != NULL; p = p->next) {
printf("%d\n", p->data);
} // or LinkedL *p = n1;
while (p != NULL) {
printf("%d\n", p->data);
p = p->next;
}
7. struct 内存空间
看里面最大的为基准来考虑,就是如果最大为 1 byte,则此为单元,如果 8 bytes 最大,则以此为单元,不满足的需要 padding。
#include <stdio.h>
#include <stdlib.h> struct somedata1 {
char age; // 1 byte
char weight; // 1 byte
char gender; // 1 byte
}; // aligns to 3 bytes struct somedata2 {
int age; // 4 bytes
char *weight; // 8 bytes
char gender; // 1 byte
}; // aligns to 24 bytes struct somedata3 {
int age; // 4 bytes
int weight; // 4 bytes
char gender; // 1 byte: either 'f' or 'm'
}; // aligns to 12 bytes int main() { printf("somedata1: %ld\n", sizeof(struct somedata1));
printf("somedata2: %ld\n", sizeof(struct somedata2));
printf("somedata3: %ld\n", sizeof(struct somedata3)); /* outputs:*/
/* somedata1: 3*/
/* somedata2: 24*/
/* somedata3: 12*/ return 0;
}
【423】COMP9024 Revision的更多相关文章
- 【434】COMP9024 Exercises Revision
目录: Week01 Week02 Week03 Week04 Week05 Week06 Week07 Week08 Week09 Week10 01. Week01 数字通过 #define 来定 ...
- 【433】COMP9024 复习
目录: 01. Week01 - Lec02 - Revision and setting the scene 02. Week02 - Lec01 - Data structures - memor ...
- 【411】COMP9024 Assignment1 问题汇总
1. 构建 Makefile 文件后运行错误,undefined reference to 'sqrt' 实际上是没有链接math数学库,所以要 $gcc test.c –lm //-lm就是链接到m ...
- 【432】COMP9024,Exercise9
eulerianCycle.c What determines whether a graph is Eulerian or not? Write a C program that reads a g ...
- 【403】COMP9024 Exercise
Week 1 Exercises fiveDigit.c There is a 5-digit number that satisfies 4 * abcde = edcba, that is,whe ...
- 【LeetCode】数学(共106题)
[2]Add Two Numbers (2018年12月23日,review) 链表的高精度加法. 题解:链表专题:https://www.cnblogs.com/zhangwanying/p/979 ...
- 【LeetCode】423. Reconstruct Original Digits from English 解题报告(Python)
[LeetCode]423. Reconstruct Original Digits from English 解题报告(Python) 标签: LeetCode 题目地址:https://leetc ...
- 【原】低版本MyEclipse整合高版本Tomcat
[使用工具] 1.MyEclipse_6.0.1GA_E3.3.1_FullStackInstaller 2.Tomcat 7.0 [问题描述] 直接在MyEclipse中整合,因为这个版本的MyEc ...
- 通用js函数集锦<来源于网络/自己> 【一】
通用js函数集锦<来源于网络/自己>[一] 1.返回一个全地址2.cookie3.验证用户浏览器是否是微信浏览器4.验证用户浏览器是否是微博内置浏览器5.query string6.验证用 ...
随机推荐
- archlinux 蓝牙耳机没有声音
前提 蓝牙已开,并且连接成功,但是蓝牙耳机没有声音. 安装 pacman -S pulseaudio-bluetooth pulsemixer 切换设备输出为蓝牙耳机
- Oracle之约束
数据的完整性用于确保数据库数据遵从一定的商业的逻辑规则.在oracle中,数据完整性可以使用约束.触发器.应用程序(过程.函数)三种方法来实现,在这三种方法中,因为约束易于维护,并且具有最好的性能,所 ...
- 金蝶二次开发C#
1 建立C#类库项目 2 引用EBOS组建Kingdee.K3.BOS.PlugInModel 3 示例代码 usingSystem; usingSystem.Collections.Generic; ...
- AtCoder NIKKEI Programming Contest 2019 E. Weights on Vertices and Edges (并查集)
题目链接:https://atcoder.jp/contests/nikkei2019-qual/tasks/nikkei2019_qual_e 题意:给出一个 n 个点 m 条边的无向图,每个点和每 ...
- Codeforces Round #597 (Div. 2) D. Shichikuji and Power Grid
链接: https://codeforces.com/contest/1245/problem/D 题意: Shichikuji is the new resident deity of the So ...
- 使用集合方式注入IoC
使用集合方式注入Ioc 1.创建类 //集合 private String[] arrays; //list集合 private List<Integer> lists; //map集合 ...
- E:nth-last-child(n)
E:nth-last-child(n) 语法: E:nth-last-child(n) { sRules } 说明: 匹配父元素的倒数第n个子元素E,假设该子元素不是E,则选择符无效.大理石平台维修 ...
- 搭建自己的博客(九):使用shell模式批量添加博客文章并增加分页功能
想做个博客分页功能,但是没有太多的文章.所以使用shell命令行创建多篇文章. 1.打开pycharm下的terminal终端 python manage.py shell # 打开python终端 ...
- LBA逻辑块地址
LBA简介 磁盘读取发展 IO操作读取硬盘的三种方式: chs方式 :小于8G (8064MB) LBA28方式:小于137GB LBA48方式:小于144,000,000 GB LBA方式访问使用了 ...
- angularJs driective指令小实例
做一个下拉菜单,体会指令各参数的作用 html代码 <script type="text/ng-template" id="mydropdown.html" ...