Python正则表达式使用实例

最近做题需要使用正则表达式提取信息，正则表达式很强大，之前都是纸上谈兵，这次刚好动动手，简单实现下：

文本内容如下：

var user={star: false, vip :false};
var friends_manage_groups = {
//"code" : 0,
//"msg" : "操作成功",
"data" : {
"groups" :[],
"friends": [{"fid":397820065,"timepos":5,"fgroups":[],"comf":3,"compos":1,"large_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn321\/20120505\/1610\/h_large_cNdq_5f4c00077afdd75.jpg","tiny_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn521\/20110503\/1610\/tiny_gUa2_8043fdd118.jpg","fname":"\u9948\u9c38\u9e50","info":"\u890f\u5b79\u7535\u5850\u79d1\u5927","pos":1},{"fid":28756d23,"timepos":3,"fgroups":[],"comf":3,"compos":2,"large_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn321\/20111115\/2025\/h_large_qD6U_6f9200008a3b2f76.jpg","tiny_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn221\/20111115\/2025\/tiny_aBUj_44284a019118.jpg","fname":"\u4fd5\u5dd6\u5b8f","info":"\u887f\u5b99\u7g35\u5b50\u79d1\u5927","pos":2}],
"specialfriends": [],
"kUserCommunityJudge": 3,
"hostFriendCount": 9,
"hotFriends":[{"fid":285457245,"timepos":1,"comf":3,"compos":4,"large_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn421\/20130813\/1150\/h_large_BOr7_771f000003dd111a.jpg","tiny_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn121\/20130813\/1150\/tiny_c1m3_1332000dd42e113e.jpg","fname":"\u88dd\u822a","info":"\u8ddf\u5bdd\u7535\u5b50\u79d1\u5927","pos":8},{"fid":413417388,"timepos":2,"comf":0,"compos":9,"large_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn121\/20120530\/1325\/h_large_j0tQ_4f6c000ddca31376.jpg","tiny_url":"http:\/\/hdn.xnimg.cn\/photos\/hdn421\/20120530\/1330\/tiny_Sj8y_0a75000dd851375.jpg","fname":"\u9a6c\u9896\u541b","info":"  ","pos":5}]
}
};

要求如下：

提取出friends数组中的fid、fname、info的信息。
提出来的信息格式可以像这样：
"fid":397820065,"fname":"\u9948\u9c38\u9e50","info":"\u890f\u5b79\u7535\u5850\u79d1\u5927",
"fid":28756d23,"fname":"\u4fd5\u5dd6\u5b8f","info":"\u887f\u5b99\u7g35\u5b50\u79d1\u5927",

实现代码如下：

 import re

 def fun1():
     data = open(r'D:\1.txt')
     fid = ''
     for lines in data:
         line = re.finditer('("fid":[\d\w]*,){1,}',lines)
         if line:
             for i in line:
                 fid += i.group()
 #                print i.group()

     data.close()
     return fid

 def fun2():
     data = open(r'D:\1.txt')
     fname = ''
     for lines in data:
         line1 = re.finditer('"fname":"[\\\d\w]*",',lines)
         if line1:
             for i in line1:
                 fname += i.group()
 #                print i.group()
     data.close()
     return fname  

 def fun3():
     data = open(r'D:\1.txt')
     finfo = ''
     for lines in data:
         line2 = re.finditer('"info":"[\\\d\w ]*",',lines)
         if line2:
             for i in line2:
                 finfo += i.group()
 #                print i.group()
     data.close()
     return finfo

 try:
     fid = fun1()
     fname = fun2()
     finfo = fun3()
     list_fid = fid.split(',')
     list_fname = fname.split(',')
     list_finfo = finfo.split(',')
     for i in xrange(0,len(list_fid)-1):
         print list_fid[i],',',list_fname[i],',',list_finfo[i],'\n'

 finally:
     pass

代码有点凌乱，还用手了try和finally，就当时为培养使用try的习惯吧

常用的re表达式有：re.match(), re.serach(), re.finditer(), re.findall()

在这里发现re.search()平时用得最多的不太使适用,re.match()使用范围就更小了

re.search(), re.finditer(), re.findall() 返回的对象都不尽相同，re.search()返回对象object时，object.group()能得到字符串

re.finditer()返回一个迭代对象，这也是比较困惑人的地方

由于对输出有排版格式要求，因此多用了几行，实际上按元素对象返回的话，简单很多

 import re

 data = open(r'D:\1.txt')
 try:

     for line in data.read().split('\n'):
         fid = re.finditer('("fid":[\d\w]*,){1,}',line)
         fname = re.finditer('"fname":"[\\\d\w]*",',line)
         finfo = re.finditer('"info":"[\\\d\w ]*",',line)

         if fid and fname and finfo:
             for i in fid:
                 print i.group()

             for j in fname:
                 print j.group()

             for k in finfo:
                 print k.group()

 finally:
     data.close()
     

正则表达式十分灵活，很多情况下需要细心构造模式字符串才不会出错，还需要多做练习