HDU4819 Mosaic

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本文版权归ljh2000和博客园共有,欢迎转载,但须保留此声明,并给出原文链接,谢谢合作. 本文作者:ljh2000 作者博客:http://www.cnblogs.com/ljh2000-jump/转载请注明出处,侵权必究,保留最终解释权! Problem Description The God of sheep decides to pixelate some pictures (i.e., change them into pictures with mosaic). Here's h…

HDU4819 Mosaic【树套树】

LINK 题目大意给你一个\(n*n\)矩阵,每个点有初始权值 q次询问每次把一个矩形的中心节点变成这个矩形中最大值和最小值的平均数思路很显然的树套树啊就是一开始傻逼了没想到怎么去维护这个东西其实很简单对于每个内层树,如果属于外层树的叶子节点,那么可以直接暴力更新,复杂度\(O(log(n))\) void modify_y(int t, int l, int r, int pos, int vl, int id) { if (l == r) { minv[id][t] = vl;…

HDU 4819 Mosaic （二维线段树）

Mosaic Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 102400/102400 K (Java/Others)Total Submission(s): 213 Accepted Submission(s): 50 Problem Description The God of sheep decides to pixelate some pictures (i.e., change them into picture…

HDU 4819 Mosaic(13年长春现场二维线段树)

HDU 4819 Mosaic 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4819 题意:给定一个n*n的矩阵,每次给定一个子矩阵区域(x,y,l),求出该区域内的最大值(A)和最小值(B),输出(A+B)/2,并用这个值更新矩阵[x,y]的值思路:裸的二维线段树,用树套树实现 # include<cstdio> # include<cstring> # include<algorithm> using namesp…

URAL Mosaic（并查集）（欧拉回路）

Mosaic Time limit: 0.25 secondMemory limit: 64 MB There's no doubt that one of the most important and crucial things to do in this world is to bring up children. May be, if you study properly and reach good results at the competition you'll get a pos…

Mosaic HDU 4819 二维线段树入门题

Mosaic Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 102400/102400 K (Java/Others)Total Submission(s): 904 Accepted Submission(s): 394 Problem Description The God of sheep decides to pixelate some pictures (i.e., change them into pictur…

HDU 4819 Mosaic 二维线段树

Mosaic Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=95149#problem/G Description The God of sheep decides to pixelate some pictures (i.e., change them into pictures with mosaic). Here's how he is go…