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概率dp HDU 3853

H - LOOPS Time Limit:5000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit cid=60444#status//H/0" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" style="display:inline-block; positi…

HDU 3853：LOOPS（概率DP）

http://acm.split.hdu.edu.cn/showproblem.php?pid=3853 LOOPS Problem Description Akemi Homura is a Mahou Shoujo (Puella Magi/Magical Girl). Homura wants to help her friend Madoka save the world. But because of the plot of the Boss Incubator, she is t…

HDU 3853 LOOPS 期望dp

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3853 LOOPS Time Limit: 15000/5000 MS (Java/Others)Memory Limit: 125536/65536 K (Java/Others) 问题描述 Akemi Homura is a Mahou Shoujo (Puella Magi/Magical Girl). Homura wants to help her friend Madoka save t…

HDU 3853 LOOPS：期望dp【网格型】

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3853 题意: 有一个n*m的网格. 给出在每个格子时:留在原地.向右走一格,向下走一格的概率. 每走一格会消耗2点体力. 问你从(1,1)到达终点(n,m)消耗体力的期望. 题解: 表示状态: dp[i][j] = rest steps(剩余路程花费体力的期望) i,j:现在的位置找出答案: ans = dp[0][0] 如何转移: 期望dp的套路:考虑子期望... now: dp[i][j] 能…

hdu 3853（数学期望入门）

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=3853 LOOPS Time Limit: 15000/5000 MS (Java/Others) Memory Limit: 125536/65536 K (Java/Others) Total Submission(s): 2512 Accepted Submission(s): 1022 Problem Description Akemi Homura is a Mahou Shou…

AC日记——LOOPS hdu 3853

3853 思路: 概率dp求期望: 代码: #include <cstdio> #include <cstring> #include <iostream> using namespace std; #define maxn 1005 int n,m; ],dp[maxn][maxn]; int main() { while(scanf("%d%d",&n,&m)!=EOF) { memset(dp,,,sizeof(p)); ;i&…

HDU 3853(期望DP)

题意: 在一个r*c的网格中行走,在每个点分别有概率向右.向下或停止不动.每一步需要的时间为2,问从左上角走到右下角的期望时间. SOL: 非常水一个DP...(先贴个代码挖个坑 code: /*========================================================================== # Last modified: 2016-01-20 23:08 # Filename: HDU3853.cpp # Description: ====…