HDOJ 4414 Finding crosses 暴力!】的更多相关文章

Finding crosses Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1631 Accepted Submission(s): 868 Problem Description The Nazca Lines are a series of ancient geoglyphs located in the Nazca Desert i…
题目:http://acm.hdu.edu.cn/showproblem.php?pid=4414 CSUST:点击打开链接 Finding crosses Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 729    Accepted Submission(s): 411 Problem Description The Nazca L…
题目链接:hdu 4414 其实是一道简单的字符型水题,不涉及任何算法,可比赛时却没能做出来,这几天的状态都差到家了... 题目大意是求有多少个满足条件的十字架,十字架的边不能有分叉路口,所以枚举每个点看是否满足条件就行,只是编码量的问题而已(感觉自己的码力不断下降了,我也不知道该怎么办好..) #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ][]; int n;…
Problem Description The Nazca Lines are a series of ancient geoglyphs located in the Nazca Desert in southern Peru. They were designated as a UNESCO World Heritage Site in 1994. The high, arid plateau stretches more than 80 kilometres (50 mi) between…
题意:在N*N的图中,找出孤立存在的十字架的个数.十字架要求为正十字,孤立表示组成十字架的‘#的周围的一格再无’#‘. dfs找出在中心的‘#’(周围四格也为‘#'),则缩小了搜索范围,再bfs找出是否是符合要求. #include <cstdio> #include <iostream> #include <cmath> #include <cstring> #include <algorithm> using namespace std; c…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4414 直接暴力判断即可. //STATUS:C++_AC_15MS_232KB #include <functional> #include <algorithm> #include <iostream> //#include <ext/rope> #include <fstream> #include <sstream> #includ…
Problem Description For hundreds of years Fermat's Last Theorem, which stated simply that for n > 2 there exist no integers a, b, c > 1 such that a^n = b^n + c^n, has remained elusively unproven. (A recent proof is believed to be correct, though it…
比赛链接: http://vjudge.net/contest/view.action?cid=47643#overview 比赛来源: 2012 ACM/ICPC Asia Regional Hangzhou Online     ID Origin Title   0 / 50 Problem A HDU 4410 Boomerang   (几何题, ★★★☆☆)   50 / 68 Problem B HDU 4411 Arrest   (费用流,待补)   46 / 122 Proble…
题目传送门 /* 题意:给出刷墙的所有的方法,求一种顺序,使得原矩阵刷成目标矩阵 暴力:(题解)我们只要每次找一行或一列颜色除了0都相同的,然后如果有对应的操作,就把这行这列都赋值成0即可 */ /************************************************ * Author :Running_Time * Created Time :2015-8-13 21:25:07 * File Name :G.cpp *************************…
题目传送门 题意:有n*m的房间,'.'表示可以被点亮,'#'表示不能被点亮,每点亮一个房间会使旁边的房间也点亮,有意盏特别的灯可以选择周围不同方向的房间点亮.问最少需要多少灯使得所有房间点亮 分析:需要被点亮的房间最多只有15个,所以考虑状压,然后暴力枚举选择哪一个当作特殊灯和枚举选择哪个方向使旁边的房间亮,注意清空vis数组需要优化,memset超时.上交6分钟1Y,Orz...额,看错榜了,最快的19分钟,而且这不是第一道水题,汗 /****************************…