hdu 3037 Saving Beans 题目大意:n个数,和不大于m的情况,结果模掉p,p保证为素数. 解题思路:隔板法,C(nn+m)多选的一块保证了n个数的和小于等于m.可是n,m非常大,所以用到Lucas定理. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; ll n, m, p; ll qPow (ll a…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4315    Accepted Submission(s): 1687 Problem Description Although winter is far away, squirrels have to work day and night to save be…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2079    Accepted Submission(s): 748 Problem Description Although winter is far away, squirrels have to work day and night to save bea…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8258    Accepted Submission(s): 3302 Problem Description Although winter is far away, squirrels have to work day and night to save be…

Saving Beans Time Limit: 3000 MS Memory Limit: 32768 K Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long cold days. After some time the squirrel fam…

主题链接:pid=3037">http://acm.hdu.edu.cn/showproblem.php?pid=3037 推出公式为C(n + m, m) % p. 用Lucas定理求大组合数取模的值 代码: #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; int t; long long n, m, p; long long pow(lo…

Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long cold days. After some time the squirrel family thinks that they have to solve a problem. They supp…

解题思路: 直接求C(n+m , m) % p , 由于n , m ,p都非常大,所以要用Lucas定理来解决大组合数取模的问题. #include <string.h> #include <iostream> #include <algorithm> #include <vector> #include <queue> #include <set> #include <map> #include <string&g…

题意:问用不超过 m 颗种子放到 n 棵树中,有多少种方法. 析:题意可以转化为 x1 + x2 + .. + xn = m,有多少种解,然后运用组合的知识就能得到答案就是 C(n+m, m). 然后就求这个值,直接求肯定不好求,所以我们可以运用Lucas定理,来分解这个组合数,也就是Lucas(n,m,p)=C(n%p,m%p)* Lucas(n/p,m/p,p). 然后再根据费马小定理就能做了. 代码如下: 第一种: #pragma comment(linker, "/STACK:10240…

Saving Beans Time Limit: 3000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 303764-bit integer IO format: %I64d      Java class name: Main   Although winter is far away, squirrels have to work day and night to save beans. T…

如果您有n+1树,文章n+1埋不足一棵树m种子,法国隔C[n+m][m] 大量的组合,以取mod使用Lucas定理: Lucas(n,m,p) = C[n%p][m%p] × Lucas(n/p,m/p,p) ; Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2314    Accepted Submissi…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5769    Accepted Submission(s): 2316 Problem Description Although winter is far away, squirrels have to work day and night to save b…

acm.hdu.edu.cn/showproblem.php?pid=3037 [题意] m个松果,n棵树 求把最多m个松果分配到最多n棵树的方案数 方案数有可能很大,模素数p 1 <= n, m <= 1000000000, 1 < p < 100000 [思路] 答案为C(n+m,m)%p 对于C(n, m) mod p.这里的n,m,p(p为素数)都很大的情况.就不能再用C(n, m) = C(n - 1,m) + C(n - 1, m - 1)的公式递推了.这里用到Luca…

作者:jostree 转载请注明出处 http://www.cnblogs.com/jostree/p/4092939.html 题目链接:hdu 5025 Saving Tang Monk 状态压缩dp+广搜 使用dp[x][y][key][s]来记录孙悟空的坐标(x,y).当前获取到的钥匙key和打死的蛇s.由于钥匙具有先后顺序,因此在钥匙维度中只需开辟大小为10的长度来保存当前获取的最大编号的钥匙即可.蛇没有先后顺序,其中s的二进制的第i位等于1表示打死了该蛇,否则表示没打死.然后进行广度…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long c…

hdu3037 Saving Beans 题意:n个不同的盒子,每个盒子里放一些球(可不放),总球数<=m,求方案数. $1<=n,m<=1e9,1<p<1e5,p∈prime$ 卢卡斯(Lucas)定理(计算组合数 防爆精度) $lucas(n,m,p)=lucas(n/p,m/p,p)*C(n\%p,m\%p,p)$ $lucas(n,0,p)=1$ 老套路,插板法. 设m个球都要放,多一个盒子轻松解决. 根据插板法得方案数$=C(n+m,n)$ 跑一遍Lucas. en…

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4153    Accepted Submission(s): 1607 Problem Description Although winter is far away, squirrels have to work day and night to save be…

http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…

Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long cold days. After some time the squirrel family thinks that they have to solve a problem. They supp…

#include<cstdio> #include<cstdlib> #include<algorithm> #include<cstring> #include<vector> #define MAXN 100000+10 #define ll long long #define pb push_back #define ft first #define sc second #define mp make_pair #define pil pa…

排列组合 啊……这题是要求c(n-1,0)+c(n,1)+c(n+1,2)+......+c(n+m-1,m) 这个玩意……其实就等于c(n+m,m) 好吧然后就是模P……Lucas大法好= = 我SB地去预处理<P的所有fac和inv了……果断TLE 事实上Lucas时对于<P的部分直接暴力算就好了 //HDOJ 3037 #include<cstdio> #include<cstdlib> #include<cstring> #include<io…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4308 Saving Princess claire_ Description Princess claire_ was jailed in a maze by Grand Demon Monster(GDM) teoy.Out of anger, little Prince ykwd decides to break into the maze to rescue his lovely Prince…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=5025 Saving Tang Monk Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3242    Accepted Submission(s): 1127 Problem Description <Journey to the West>…

题目来源:Saving HDU 题意分析: XHD有个容量为v的口袋,有n个宝贝,每种宝贝的价值不一样,每种宝贝单位体积的价格也不一样,宝贝可以分割,分割后的价值和对应的体积成正比.求XHD最多能取回多少价值的宝贝? 我的思路 一开始我没想明白,认为给的价值是一种宝贝的总价值,所以样例我都解释不了,想到给的价值是单位体积的价值,而不是总价值,就可以解释了,理解题意是很重要的,要不然下不去手啊Orz. 接下来就是贪心了,体积都是一样的,如果想要拿到价值最高的东西,那么每体积的价值都要尽可能高才行,…

解题思路:排序后贪心,和fatmouse's  trade 类似 Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5837    Accepted Submission(s): 2692 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏…

Description <Journey to the West>(also <Monkey>) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng'en during the Ming Dynasty. In this novel, Monkey King Sun Wukong, pig Zhu Bajie and Sha Wujing, escor…

Saving Tang Monk Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 941    Accepted Submission(s): 352 Problem Description <Journey to the West>(also <Monkey>) is one of the Four Great Clas…

http://acm.hdu.edu.cn/showproblem.php?pid=1245 #include <cstdio> #include <cstring> #include <cmath> #include <queue> #include <algorithm> #define maxn 500 using namespace std; const double inf=99999999.0; int n,m; double d;…

Problem Description <Journey to the West>(also <Monkey>) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng'en during the Ming Dynasty. In this novel, Monkey King Sun Wukong, pig Zhu Bajie and Sha Wujin…

Problem Description <Journey to the West>(also <Monkey>) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng'en during the Ming Dynasty. In this novel, Monkey King Sun Wukong, pig Zhu Bajie and Sha Wujin…