[求助][SPOJ MARIOGAM]-高斯消元(内含标程,数据等)

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[求助][SPOJ MARIOGAM]-高斯消元(内含标程,数据等)

小蒟蒻开始做概率的题之后,遇到了这道题,然而,他发现自己的程序调试了无数次也无法通过,系统总是返回令人伤心的WA, 于是,他决定把这一天半的时间收集到的资料放在网上, 寻求大家的帮助, 也可以节省后来人的时间. 题目描述和题解就不写了. 易错数据: 1 4 $#99 1 4 A5a$ 2 3 $aA 1## 3 3 4A# ##$ 1a! 大数据: 15 15 $A............. aaaaaaaaaaaaaa. .........#!1... .aaaaaaaaaaaaaa ....…

SPOJ HIGH(生成树计数，高斯消元求行列式)

HIGH - Highways no tags In some countries building highways takes a lot of time... Maybe that's because there are many possiblities to construct a network of highways and engineers can't make up their minds which one to choose. Suppose we have a lis…

单（single）：换根dp，表达式分析，高斯消元

虽说这题看大家都改得好快啊,但是为什么我感觉这题挺难.(我好菜啊) 所以不管怎么说那群切掉这题的大佬是不会看这篇博客的所以我要开始自嗨了. 这题,明显是树dp啊.只不过出题人想看你发疯,询问二合一了而已. 对于给出了a数组要求b数组的询问,想象一下怎么求. 你先yy一棵树,我懒得画了...父节点叫fa,子节点叫s 那么想一想对于s来说它的答案来自与哪里. 首先是它的子树,设以s为根的子树的a值和为w[s],而子树对它的总贡献是son[s] 那么这样理解:所有子树里的点都需要先走到s的直接儿子们,…

SPOJ HIGH Highways ——Matrix-Tree定理高斯消元

[题目分析] Matrix-Tree定理+高斯消元求矩阵行列式的值,就可以得到生成树的个数. 至于证明,可以去看Vflea King(炸树狂魔)的博客 [代码] #include <cmath> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define eps 1e-8 #define ma…

【SPOJ 104】HIGH - Highways (高斯消元)

题目描述 In some countries building highways takes a lot of time- Maybe that's because there are many possiblities to construct a network of highways and engineers can't make up their minds which one to choose. Suppose we have a list of cities that can b…