Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3797    Accepted Submission(s): 1776 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…
Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8845    Accepted Submission(s): 4104 Problem Description It is well known that AekdyCoin is good at string problems as well as n…
Count the string Problem Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:s: "abab"The prefi…
题目 以下不是KMP算法—— 以下是kiki告诉我的方法,好厉害的思维—— 就是巧用标记,先标记第一个出现的所有位置,然后一遍遍从标记的位置往下找. #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int main() { ],shunxu; ]; scanf("%d",&t); while(t--) { memset(xiabiao,…
Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4105    Accepted Submission(s): 1904 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…
Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 14096    Accepted Submission(s): 6462 Problem Description It is well known that AekdyCoin is good at string problems as well as…
[题意概述] 给定一个文本字符串,找出所有的前缀,并把他们在文本字符串中的出现次数相加,再mod10007,输出和. [题目分析] 利用kmp算法的next数组 再加上dp [存在疑惑] 在分析next数组和dp之间的关系,结论是 dp[i] = (dp[next[i]]+1); 搞不懂之间存在的联系 [AC] #include <bits/stdc++.h> ],next[]; ]; void getnext() { ,j=-; next[]=-; while(i<m) { ||s[i…
KMP算法用于模式串字符匹配,因为没有提前预习,上课时听得云里雾里,后来回去看了一晚上,翻了一些网上的讲解才理解了.我简单讲一下,我们在一串字符串A里搜索匹配另一段字符串B时,思路最简单方法的就是从第一位开始一个个对照匹配,出现错误就移动到第二个字符继续匹配,不匹配再第三个.但这样毕竟性能比较低,KMP引入了一个next数组,先将需要匹配的这段字符B计算出next值,在AB匹配的时候如果出现不匹配的情况,就根据next值跳到对应的字符继续匹配,所以中间就省略了一些不必要的匹配,从而提高了性能.n…
It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:  s: "abab"  The prefixes are: "a", "ab&…
题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=3336 如果你是ACMer,那么请点击看下 题意:求每一个的前缀在母串中出现次数的总和. AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include…