Java [leetcode 21]Merge Two Sorted Lists

【Java [leetcode 21]Merge Two Sorted Lists】的更多相关文章

Java [leetcode 21]Merge Two Sorted Lists

题目描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题思路: 题目的意思是将两个有序链表合成一个有序链表. 逐个比较加入到新的链表即可. 代码如下: public static ListNode mergeTwoLists(ListNode l1, Li…

[LeetCode] 21. Merge Two Sorted Lists 合并有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…

[LeetCode] 21. Merge Two Sorted Lists 混合插入有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…

[leetcode] 21. Merge Two Sorted Lists (Easy)

合并链表 Runtime: 4 ms, faster than 100.00% of C++ online submissions for Merge Two Sorted Lists. class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { //1 2 4 . 1 3 4 ListNode *res = ); ListNode *cur = res; while (l1 != NULL &&am…

leetcode 21.Merge Two Sorted Lists ,java

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解决方案:276ms /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next…

LeetCode 21. Merge Two Sorted Lists （合并两个有序链表）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…

# 蜗牛慢慢爬 LeetCode 21. Merge Two Sorted Lists [Difficulty: Easy]

题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 翻译合并两个有序的链表 Hints Related Topics: LinkedList 参考归并排序-维基百科,可以递归也可以迭代,基本的链表操作代码 Java /** * Definition for…

LeetCode 21 -- Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ListNode p1 = l1; ListNode p2 = l2; ListNode fakeH…

Java [leetcode 23]Merge k Sorted Lists

题目描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路: 分治方法.将K个List不断地分解为前半部分和后半部分.分别进行两个List的合并.最后将合并的结果合并起来. 代码如下: /** * Definition for singly-linked list. * public class ListNode { * int val;…

[LeetCode] 21. Merge Two Sorted Lists 解题思路

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 问题:将两个已排序的列表,合并为一个有序列表. 令 head 为两个列表表头中较小的一个,令 p 为新的已排序的最后一个元素.令 l1, l2 分别为两个列表中未排序部分的首节点.依次将 l1, l2 中的较小值追加…

Leetcode 21. Merge Two Sorted Lists（easy）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 递归实现: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(i…

(链表) leetcode 21. Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 中文:将两个有序链表合并为一个新的有序链表并返回.新链表…

[leetcode]21. Merge Two Sorted Lists合并两个链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目合并两个链表思路用dummy, 因为需要对头结…

[LeetCode] 21. Merge Two Sorted Lists ☆

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解法: 新建一个链表,依次比较两个链表的头元素,把较小的移到新链表中,直到有一个为空,再将另一个链表剩余元素移到新链表末尾. 采用循环的方式,代码如下: /** * Definition for singly-lin…

[LeetCode]21. Merge Two Sorted Lists合并两个有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 list顺序合并就可以了 /** * Definitio…

LeetCode 21. Merge Two Sorted Lists合并两个有序链表 (C++)

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返…

LeetCode 21 Merge Two Sorted Lists （有序两个链表整合）

题目链接 https://leetcode.com/problems/merge-two-sorted-lists/?tab=Description Problem: 已知两个有序链表(链表中的数值递增排列).将这两个链表进行合并操作,并且满足递增排列即合并后仍为有序链表. 递归进行合并操作.mergeTwoList(ListNode list1, ListNode list2) 当list1==null时 return list2; 当list2==null时…

Leetcode 21 Merge Two Sorted Lists 链表

合并两个已排序的链表,考到烂得不能再烂的经典题,但是很多人写这段代码会有这样或那样的问题这里我给出了我的C++算法实现 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(…

LeetCode 21. Merge Two Sorted Lists（c++)

要定义两个链表判断时依次对应每一个链表的值进行判断即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { L…

leetcode 21 Merge Two Sorted Lists 合并两个有序链表

描述: 合并两个有序链表. 解决: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1) return l2; if (!l2) return l1; if (!l1 && !l2) return NULL; ListNode* ret = ); ListNode* now = ret; while (l1 || l2) { if (!l1) { now->next = l2; break; } else if…

LeetCode 21. Merge Two Sorted Lists（合并两个有序链表）

题意:合并两个有序链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if(l1 == NULL) retu…

Java for LeetCode 023 Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路一: 之前我们有mergeTwoLists(ListNode l1, ListNode l2)方法,直接调用的话,需要k-1次调用,每次调用都需要产生一个ListNode[],空间开销很大.如果采用分治的思想,对相邻的两个ListNode进行mergeTwoLists,每次将规模减少一半,直到…

[Leetcode][Python]21: Merge Two Sorted Lists

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 21: Merge Two Sorted Listshttps://oj.leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list.The new list should be made by splicing together…

leetCode练题——21. Merge Two Sorted Lists（照搬大神做法）

1.题目 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4-&g…

21. Merge Two Sorted Lists(合并2个有序链表)

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists 需要排序!!! [2,4][1] 输出1 2 4 而不是2 4 1 递归版!! class Solution { public ListNode mergeTwo…

21. Merge Two Sorted Lists【easy】

21. Merge Two Sorted Lists[easy] Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解法一: /** * Definition for singly-linked list. * struct ListNode { * int val…