E. Minimal Labels time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given a directed acyclic graph with n vertices and m edges. There are no self-loops or multiple edges between any p…

这两道题都需要用到拓扑排序,所以先介绍一下什么叫做拓扑排序. 这里说一下我是怎么理解的,拓扑排序实在DAG中进行的,根据图中的有向边的方向决定大小关系,具体可以下面的题目中理解其含义 Educational Codeforces Round 25  E. Minimal Labels 题目链接:http://codeforces.com/contest/825/problem/E 题意:给你一个有向无环图(DAG),有n个顶点,m条边,顶点的序号分别是1-n,现在给你1-n的数对n个顶点进行赋值…

逃生 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description 糟糕的事情发生啦,现在大家都忙着逃命.但是逃命的通道很窄,大家只能排成一行. 现在有n个人,从1标号到n.同时有一些奇怪的约束条件,每个都形如:a必须在b之前.同时,社会是不平等的,这些人有的穷有的富.1号最富,2号第二富,以此类推.有钱人就贿赂负责人,所以他们有一些好处. 负责人现在…

逃生 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 6686 Accepted Submission(s): 1958 Problem Description 糟糕的事情发生啦,现在大家都忙着逃命.但是逃命的通道很窄,大家只能排成一行. 现在有n个人,从1标号到n.同时有一些奇怪的约束条件,每个都形如:a必须在b之前. 同时,社会是不平等的…

B. Legacy 题目连接: http://codeforces.com/contest/786/problem/B Description Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy to Morty before bad guys catch them. There are…

题意不说了,说下思路. 给出的关系是a要求的工资要比b的工资多,因为尽可能的让老板少付钱,那么a的工资就是b的工资+1.能够确定关系为a>b,依据拓扑排序建边的原则是把"小于"关系看成有向边.那么我们能够建边v->u. #include <stdio.h> #include <string.h> #include <string> #include <iostream> #include <algorithm> #…

You are given a directed acyclic graph with n vertices and m edges. There are no self-loops or multiple edges between any pair of vertices. Graph can be disconnected. You should assign labels to all vertices in such a way that: Labels form a valid pe…

题目网址:http://codeforces.com/contest/825/problem/B 题目:   Alice and Bob play 5-in-a-row game. They have a playing field of size 10 × 10. In turns they put either crosses or noughts, one at a time. Alice puts crosses and Bob puts noughts. In current matc…

A:链接:http://codeforces.com/contest/825/problem/A 解题思路: 一开始以为是个进制转换后面发现是我想多了,就是统计有多少个1然后碰到0输出就行,没看清题意.. 实现代码: #include<bits/stdc++.h> using namespace std; int main() { ; string s; cin>>m; cin>>s; ;i<m;i++){ ') ans++; ){ cout<<ans…

题目链接:http://codeforces.com/contest/825/problem/C C. Multi-judge Solving time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Makes solves problems on Decoforces and lots of other different onlin…