CodeForces 621C Wet Shark and Flowers】的更多相关文章

方法可以转化一下,先计算每一个鲨鱼在自己范围内的数能被所给素数整除的个数有几个,从而得到能被整除的概率,设为f1,不能被整除的概率设为f2. 然后计算每相邻两只鲨鱼能获得钱的期望概率,f=w[id1].f1*w[id2].f2+w[id1].f2*w[id2].f1+w[id1].f1*w[id2].f1; f*2000就是这两只鲨鱼能获得的期望金钱,然后枚举一下所有相邻的鲨鱼,累加即可. #include<cstdio> #include<cstring> #include<…
题意:输入个n和质数p,n个区间,每个区间可以等概率的任选一个数,如果选的这个区间和它下个区间选的数的积是p的倍数的话(n的下个是1),就挣2000,问挣的期望 思路:整体的期望可以分成每对之间的期望.期望=概率乘2000. 得到钱概率=1-得不到钱的概率 #include<iostream> #include<string> #include<algorithm> #include<cstdlib> #include<cstdio> #incl…
C. Wet Shark and Flowers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are n sharks who grow flowers for Wet Shark. They are all sitting around the table, such that sharks i and i …
题 There are n sharks who grow flowers for Wet Shark. They are all sitting around the table, such that sharks i andi + 1 are neighbours for all i from 1 to n - 1. Sharks n and 1 are neighbours too. Each shark will grow some number of flowers si. For i…
http://codeforces.com/problemset/problem/621/E E. Wet Shark and Blocks time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are b blocks of digits. Each one consisting of the same n digit…
B. Wet Shark and Bishops time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input output: standard output Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from…
E. Wet Shark and Blocks time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are b blocks of digits. Each one consisting of the same n digits, which are given to you in the input. Wet Sha…
题意: 不概括了..太长了.. 额第一次做这种问题 算是概率dp吗? 保存前缀项中第一个和最后一个的概率 然后每添加新的一项 就解除前缀和第一项和最后一项的关系 并添加新的一项和保存的两项的关系 这里关系指的是两者相邻会产生的额外收入(其中一个满足条件就能得到 因此公式是 2000 * (rate[a] * rate[b] + rate[a] * ( 1 - rate[b]) + rate[b] * (1 - rate[a])) 至于一开始为什么老是调不过去呢..我发现添加第三项的时候前两项是不…
记录一下每个对角线上有几个,然后就可以算了 #include<cstdio> #include<cstring> #include<cmath> #include<ctime> #include<vector> #include<algorithm> using namespace std; +; int n; long long w1[maxn]; long long w2[maxn]; long long ans; int mai…
水题 #include<cstdio> #include<cstring> #include<cmath> #include<ctime> #include<vector> #include<algorithm> using namespace std; int n; +]; int main() { scanf("%d",&n); ;i<n;i++) scanf("%lld",&…