I am going to my home. There are many cities and many bi-directional roads between them. The cities are numbered from 0 to n-1 and each road has a cost. There are m roads. You are given the number of my city t where I belong. Now from each city you h…

1002 - Country Roads I am going to my home. There are many cities and many bi-directional roads between them. The cities are numbered from 0 to n-1 and each road has a cost. There are m roads. You are given the number of my city t where I belong. Now…

 题目链接 /* Name:hdu-1102-Constructing Roads Copyright: Author: Date: 2018/4/18 9:35:08 Description: prime算法模板 */ #include <iostream> #include <cstdio> #include <cstring> #include <utility> #include <vector> using namespace std;…

题目连接: http://www.lightoj.com/volume_showproblem.php?problem=1002 题目描述: 有n个城市,从0到n-1开始编号,n个城市之间有m条边,中心城市为t,问每个城市到中心城市的最小路径的花费,路径花费大小的定义为:一条路上花费最大的边的值. 解题思路: Dijkstra的变形,用Dijkstra求出来的单源路径可以保证每条边都是最优的,所以最短路上的最长边就是所求. #include <algorithm> #include <i…

                                                                                           1002 - Country Roads    PDF (English) Statistics Forum Time Limit: 3 second(s) Memory Limit: 32 MB 点击打开链接 I am going to my home. There are many cities and many…

遇到一道题,简单说就是找一个图的最小生成树,大概有两种常用的算法:Prim算法和Kruskal算法.这里先介绍Prim.随后贴出1924的算法实现代码. Prim算法 1.概览 普里姆算法(Prim算法),图论中的一种算法,可在加权连通图里搜索最小生成树.意即由此算法搜索到的边子集所构成的树中,不但包括了连通图里的所有顶点(英语:Vertex (graph theory)),且其所有边的权值之和亦为最小.该算法于1930年由捷克数学家沃伊捷赫·亚尔尼克(英语:Vojtěch Jarník)发现:…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21947    Accepted Submission(s): 8448 Problem Description There are N villa…

Jungle Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3614    Accepted Submission(s): 2609 Problem Description The Head Elder of the tropical island of Lagrishan has a problem. A burst o…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3371 Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10313    Accepted Submission(s): 2937 Problem Description In 2100, since th…

图的连通性问题:无向图的连通分量和生成树,所有顶点均由边连接在一起,但不存在回路的图. 设图 G=(V, E) 是个连通图,当从图任一顶点出发遍历图G 时,将边集 E(G) 分成两个集合 T(G) 和 B(G).其中 T(G)是遍历图时所经过的边的集合,B(G) 是遍历图时未经过的边的集合.显然,G1(V, T) 是图 G 的极小连通子图,即子图G1 是连通图 G 的生成树. 深度优先生成森林   右边的是深度优先生成森林: 连通图的生成树不一定是唯一的,不同的遍历图的方法得到不同的生成树;从不…