给定一个仅包含小写字母的字符串,去除重复的字母使得所有字母出现且仅出现一次.你必须保证返回结果是所有可能结果中的以字典排序的最短结果.例如:给定 "bcabc"返回 "abc"给定 "cbacdcbc"返回 "acdb" 详见:https://leetcode.com/problems/remove-duplicate-letters/description/ C++: class Solution { public: str…

870. Advantage Shuffle 思路:A数组的最大值大于B的最大值,就拿这个A跟B比较:如果不大于,就拿最小值跟B比较 A可以改变顺序,但B的顺序不能改变,只能通过容器来获得由大到小的顺序,并且必须存储相应的index,因为最终需要将选择的A的数值存入与这个B相对应的index下 class Solution { public: vector<int> advantageCount(vector<int>& A, vector<int>&…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/remove-duplicate-letters/ 题目描述 Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear…

https://leetcode.com/problems/remove-duplicate-letters/ Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical o…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example 1: Input: "bcab…

题目如下: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example 1: Input:…

316. Remove Duplicate Letters Total Accepted: 2367 Total Submissions: 12388 Difficulty: Medium Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your resu…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example 1: Input: "bcab…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q…

316. 去除重复字母 给定一个仅包含小写字母的字符串,去除字符串中重复的字母,使得每个字母只出现一次.需保证返回结果的字典序最小(要求不能打乱其他字符的相对位置). 示例 1: 输入: "bcabc" 输出: "abc" 示例 2: 输入: "cbacdcbc" 输出: "acdb" PS: 我把每一个数出现的次数都拿出来,我当前字符比我栈顶的小,并且我栈顶的字符还有多的在后面,我就可以把他替换了,记录一下是否使用 clas…

316. 去除重复字母 知识点:栈:单调 题目描述 给你一个字符串 s ,请你去除字符串中重复的字母,使得每个字母只出现一次.需保证 返回结果的字典序最小(要求不能打乱其他字符的相对位置). 示例 输入:s = "bcabc" 输出:"abc" 输入:s = "cbacdcbc" 输出:"acdb" 解法一:单调 我们来仔细分析一下这道题目,它结合了很多知识点,因为题目中提出了很多要求. 1.去掉重复的:对于去重最常用的就是s…

题目介绍: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "b…

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q…

Remove Duplicate Letters I Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. Example: Given "bcabc"Return "abc" Given "cbacdcbc"Return "abcd&qu…

原题链接在这里:https://leetcode.com/problems/remove-duplicate-letters/ 题目: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexic…

题目描述: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "b…

题目 贪心方法 用一个两个数组vector<int>cnt,vector<bool>in_right_place: string res:目前符合条件的字符串,到代码结束的时候,这个res才是正确的答案 cnt数组 用于记录每个char未来会出现的次数,in_right_place数组判断这个char是否已经在正确的位置上 什么叫做未来会出现呢? 我们拿样例做为例子: 输入: "bcabc" 我们先遍历一遍所有字符串记录cnt 结果是cnt['a']=1,cnt…

问题描述 给一个字符串(只包含小写字母),删除重复的字母, 使得每个字母只出现一次.返回的结果必须是字典顺序最小的. 举例:“bcabc" -> "abc", "cbacdcbc" -> "acdb". 提示:stack.greed 解决本题的关键是如何使用贪心策略 下面C++的实现使用的是这样的策略: 令目标字符串为空,每增加一位就遍历a-z,根据条件来判断当前字符是否可以添加到目标字符串. 因为遍历顺序是字典顺序,因此只…

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example,Given1->2->3->3->4->4->5, return1->2->5.Given1->1->1->2->3, return2->3. 这题和R…

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra mem…

import java.util.*; /* 将自定义对象作为元素存到ArrayList集合中,并去除重复元素. 比如:存人对象.同姓名同年龄,视为同一个人.为重复元素. 思路: 1,对人描述,将数据封装进人对象. 2,定义容器,将人存入. 3,取出. List集合判断元素是否相同,依据是元素的equals方法. */ class Person { private String name; private int age; Person(String name,int age) { this.n…

在java开发中碰到了有些字符串是重复的,如果在进行业务处理要全部遍历太对的数据就会重复,所以在进行业务处理前进行一个去重操作. 这里由于业务需要所以先将字符串转化为string数组,使用split分割,然后将string数组一个个放到list里(list的remove可以将你不要的字符串删除掉,代参数的哦) 可以看到我使用的是list,在list里包含了一个contains函数,表示当前字符串是否与list里的元素有相同没有就add进list里 在最后还将list里的元素转化为string数组…

一: Hastset根据hashcode判断是否重复,数据不会重复 Java代码 /** List order not maintained **/ public static void removeDuplicate(ArrayList arlList) { HashSet h = new HashSet(arlList); arlList.clear(); arlList.addAll(h); } 二: 通过Hashset的add方法判断是否已经添加过相同的数据,如果已存在相同的数据则不添加…

1.去除重复字符串 package com.online.msym; import java.util.ArrayList; import java.util.Iterator; @SuppressWarnings({ "rawtypes", "unchecked" }) public class Demo1_ArrayList { public static void main(String[] args) { ArrayList list = new Array…

1. 循环list中的所有元素然后删除重复 public static List removeDuplicate(List list) { for ( int i = 0 ; i < list.size() - 1 ; i ++ ) { for ( int j = list.size() - 1 ; j > i; j -- ) { if (list.get(j).equals(list.get(i))) { list.remove(j); } } } return list; } 2. 通过H…