HDU 1034 Candy Sharing Game (模拟)】的更多相关文章

题目链接 Problem Description A number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives half of his or her can…
Candy Sharing Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4448    Accepted Submission(s): 2718 Problem Description A number of students sit in a circle facing their teacher in the cente…
Candy Sharing Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4425    Accepted Submission(s): 2698 Problem Description A number of students sit in a circle facing their teacher in the cent…
题目链接:https://cn.vjudge.net/problem/HDU-1034 水题 代码 #include <cstdio> #include <algorithm> int n; long long stu[10000+5], max, min; int func(void){ int tmp[2]={stu[0]/=2, 0}; for (int i=0; i<n; i++){ tmp[1]=stu[i+1]/=2; stu[(i+1)%n]+=tmp[0];…
这道题只要英语单词都认得,阅读没有问题,就做得出来. POJ - 1666 Candy Sharing Game Time Limit: 1000MS Memory Limit: 10000KB 64bit IO Format: %I64d & %I64u Description A number of students sit in a circle facing their teacher in the center. Each student initially has an even n…
HDU 4041 Eliminate Witches! (模拟题 ACM ICPC 2011 亚洲北京赛区网络赛题目) Eliminate Witches! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 863    Accepted Submission(s): 342 Problem Description Kaname Mado…
题目链接: Hdu 4465 Candy 题目描述: 有两个箱子,每个箱子有n颗糖果,抽中第一个箱子的概率为p,抽中另一个箱子的概率为1-p.每次选择一个箱子,有糖果就拿走一颗,没有就换另外一个箱子.问换箱子的时候,另外一个箱子中剩下糖果的期望值. 解题思路: 注意题目描述,其中任意一个箱子没有糖果,另一个箱子中剩下糖果个数的期望,而不是第一个箱子没有糖果.不是把其中一个箱子取空时,另一个箱子剩下糖果的期望,而是其中一个箱子取空再换另外一个箱子时,这个箱子的期望. 可以根据期望性质画出公式:an…
时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:248 解决:194 题目描述: A number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives h…
题意是一群孩子围成一个圈,每个人把手中的糖果分一半给右边的人,若分过之后手中的糖果数是奇数,则由老师提供一颗糖果给他,问这样传递多少圈所有人的糖果数都能相等,最终每人手里的糖果数是多少. 由于题中已经解释了结果是有限的数,那么就直接模拟,要注意分的时候是从前面的人往后面传递. 代码如下: #include <bits/stdc++.h> using namespace std; ],pre[]; bool judge() { ; i < n; ++i) ]) return false;…
Thickest Burger Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 63    Accepted Submission(s): 60 Problem Description ACM ICPC is launching a thick burger. The thickness (or the height) of a piec…