127. Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the wo…
127. Word Ladder 这道题使用bfs来解决,每次将满足要求的变换单词加入队列中. wordSet用来记录当前词典中的单词,做一个单词变换生成一个新单词,都需要判断这个单词是否在词典中,不在词典中就不能加入队列. pathCnt用来记录遍历到的某一个词使用的次数,做一个单词变换生成一个新单词,都需要判断这个单词是否在pathCnt中,如果在,则说明之前已经达到过,这次不用再计算了,因为这次计算的path肯定比之前多.pathCnt相当于剪枝. class Solution { pub…
126. Word Ladder II 题目 Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist…
public class DemoTest { public static void main(String[] args) { System.)); } /** * 有一个字符串A 有一个字符串B 想要从A转换到B,只能一次一次转换,每次转换要把字符串A中的一个字符全部转换成另一个字符, * 求字符串A能不能转换成字符串B.例如 "abc" -- "bbc" --- "ddc" 判断转换是否成立 * */ public static boole…
题目: Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list.…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the word list For…
原题地址 既然是求最短路径,可以考虑动归或广搜.这道题对字典直接进行动归是不现实的,因为字典里的单词非常多.只能选择广搜了. 思路也非常直观,从start或end开始,不断加入所有可到达的单词,直到最终到达另一端.本质上广度优先遍历图. 需要注意的是,拓展下一个单词时不能对字典进行枚举,因为字典里的单词太多.幸好单词本身都不长,所以直接枚举单词所有可能的变形,看看在dict中出现没有. 当然还不止这些,上面的做法仍然会超时,需要添加剪枝策略: 1. 如果某个单词在以前遍历过了,那么以后都不用再考…
Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time    Each intermediate word must exist in the dictionary For example, Given:start = "…
题目: Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the word list…
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题目如下: 解题思路:DFS或者BFS都行.本题的关键在于减少重复计算.我采用了两种方法:一是用字典dic_ladderlist记录每一个单词可以ladder的单词列表:另外是用dp数组记录从startword开始到wordlist每一个word的最小转换次数,这一点非常重要,可以过滤很多无效的运算. 代码如下: class Solution(object): def getLadderList(self, w,d): l = [] r = [] for i in xrange(26): l.a…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the word list For…
https://leetcode.com/problems/word-ladder-ii/ Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each inte…
Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…
Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start…
Leetcode之广度优先搜索(BFS)专题-127. 单词接龙(Word Ladder) BFS入门详解:Leetcode之广度优先搜索(BFS)专题-429. N叉树的层序遍历(N-ary Tree Level Order Traversal) 相同思路的题目:Leetcode之广度优先搜索(BFS)专题-752. 打开转盘锁(Open the Lock) 给定两个单词(beginWord 和 endWord)和一个字典,找到从 beginWord 到 endWord 的最短转换序列的长度.…
题目: Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the wor…
给出两个单词(beginWord 和 endWord)和一个字典,找到从 beginWord 到 endWord 的最短转换序列,转换需遵循如下规则:    每次只能改变一个字母.    变换过程中的中间单词必须在字典中出现.例如,给出:beginWord = "hit"endWord = "cog"wordList = ["hot","dot","dog","lot","lo…
Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…
题意:给出两个单词,以及一个set集合,当中是很多的单词.unordered_set是无序的集合,也就是说找的序列也是无序的了,是C++11的标准,可能得升级你的编译器版本了.要求找出一个从start到end这两个单词的变换序列.从start开始,每次可以变一个字母,且所变之后的单词必须在set中,最后要求变成end,问经过了多少个中间变换?注意要加多2次(start和end也要算),这是规定. 思路:广度搜索,以start为树根,一层一层扩展,直到找到end,返回数的深度即可.步骤是这样的,先…
Word Ladder Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example,…
[题目] Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start =…
Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the word li…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…
Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…
127. Word LadderGiven two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exis…
[题目] Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:…
原题地址 BFS Word Ladder II的简化版(参见这篇文章) 由于只需要计算步数,所以简单许多. 代码: int ladderLength(string start, string end, unordered_set<string> &dict) { if (start == end) ; unordered_set<string> old; queue<string> layer; ; layer.push(start); while (!laye…