题目 在一个小镇里,按从 1 到 N 标记了 N 个人.传言称,这些人中有一个是小镇上的秘密法官. 如果小镇的法官真的存在,那么: 小镇的法官不相信任何人. 每个人(除了小镇法官外)都信任小镇的法官. 只有一个人同时满足属性 1 和属性 2 . 给定数组 trust,该数组由信任对 trust[i] = [a, b] 组成,表示标记为 a 的人信任标记为 b 的人. 如果小镇存在秘密法官并且可以确定他的身份,请返回该法官的标记.否则,返回 -1. 示例 1: 输入:N = 2, trust =…

In a town, there are N people labelled from 1 to N.  There is a rumor that one of these people is secretly the town judge. If the town judge exists, then: The town judge trusts nobody. Everybody (except for the town judge) trusts the town judge. Ther…

https://leetcode.com/problems/find-the-town-judge/ In a town, there are N people labelled from 1 to N.  There is a rumor that one of these people is secretly the town judge. If the town judge exists, then: The town judge trusts nobody. Everybody (exc…

problem 997. Find the Town Judge solution: class Solution { public: int findJudge(int N, vector<vector<int>>& trust) { vector<); ]]--; balance[t[]]++; } ; i<=N; i++) { ) return i; } ; } }; 参考 1. Leetcode_easy_997. Find the Town Judge…

题目如下: In a town, there are N people labelled from 1 to N.  There is a rumor that one of these people is secretly the town judge. If the town judge exists, then: The town judge trusts nobody. Everybody (except for the town judge) trusts the town judge…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 度 日期 题目地址:https://leetcode.com/problems/rotting-oranges/ 题目描述 In a town, there are N people labelled from 1 to N. There is a rumor that one of these people is secretly the town…

1.题目描述 2.问题分析 使用map set数据结构. 3.代码 int findJudge(int N, vector<vector<int>>& trust) { ) ; ; map<int, int> m; set<int> s; for (auto it = trust.begin(); it != trust.end(); it++) { m[(*it).back()]++; s.insert((*it).front()); } int…

这是悦乐书的第373次更新,第400篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第234题(顺位题号是997).在一个城镇,有N个人从1到N标记.有传言说其中一个人是秘密的镇法官. 如果镇法官存在,那么: 镇法官不信任任何人. 每个人(镇法官除外)都信任镇法官. 只有一个人满足前两条. 给定一个trust数组,一对trust[i] = [a,b]表示被标记为a的人信任标记为b的人. 如果镇法官存在并且可以识别,则返回镇法官的标签.否则,返回-1. 例如: 输入:N…

Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may exist one celebrity. The definition of a celebrity is that all the other n - 1people know him/her but he/she does not know any of them. Now you want to find…

原题链接在这里:https://leetcode.com/problems/find-the-celebrity/ 题目: Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may exist one celebrity. The definition of a celebrity is that all the other n - 1people know him/h…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

图基础 图(Graph)应用广泛,程序中可用邻接表和邻接矩阵表示图.依据不同维度,图可以分为有向图/无向图.有权图/无权图.连通图/非连通图.循环图/非循环图,有向图中的顶点具有入度/出度的概念. 面对图相关问题,第一步是将问题转为用图表示(邻接表/邻接矩阵),二是使用图相关算法求解. 相关LeetCode题: 997. Find the Town Judge  题解 1042. Flower Planting With No Adjacent  题解 图的遍历(DFS/BFS) 图的遍历/搜索…

Suppose you are at a party with n people (labeled from 0 to n - 1) and among them, there may exist one celebrity. The definition of a celebrity is that all the other n - 1 people know him/her but he/she does not know any of them. Now you want to find…

Contest 121 (题号981-984)(2019年1月27日) 链接:https://leetcode.com/contest/weekly-contest-121 总结:2019年2月22日补充的报告.当时不想写.rank:1093/3924,AC:2/4.还是太慢了. [984]String Without AAA or BBB(第一题 4分)(Greedy, M) 给了两个数字,A 代表 A 个 ‘A’, B 代表 B 个‘B’ 在字符串里面.返回一个可行的字符串,字符串中包含 A…

Highways description The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has a very poor system of public highways. The Flatopian government is aware of this problem and has already constructed a number of highways connecting som…

题目链接 http://codeforces.com/gym/101102/problem/C problem description Judge Bahosain was bored at ACM AmrahCPC 2016 as the winner of the contest had the first rank from the second hour until the end of the contest. Bahosain is studying the results of t…

Problem 1074: Hey Judge Time Limits:  1000 MS   Memory Limits:  65536 KB 64-bit interger IO format:  %lld   Java class name:  Main   Description Judge Nicole collected 7 ideas for problems of different levels, she wants to create 5 problems for the n…

转自:http://www.cnblogs.com/chouti/p/5752819.html Special Judge:当正确的输出结果不唯一的时候需要的自定义校验器 首先有个框架 #include<fstream> ifstream fin,fout,fstd ofstream fscore,freport; double Judge(){ } int main(int argc,char *argv[]) { //put something to fstreams... //Judge…

前段时间准备华为机试,正好之前看了一遍<剑指 Offer>,就在九度 Online Judge 上刷了书中的题目,使用的语言为 C++:只有3题没做,其他的都做了. 正如 Linus Torvalds 所言“Talk is cheap, show me the code!",详见托管在 Github 的源码:点击打开链接(核心部分有注释). 难度总结:有些可以不必要像书中那样保存中间结果,直接输出,也就可以不使用书中的算法:有些题目在书中题目的基础上加了更多的要求,也更难实现一点.…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5391 相关数论结论: 威尔逊定理——当且仅当p为素数时:( p -1 )! ≡ p-1 ( mod p ) 这道题一开始看到的时候以为是暴力的题目,快速阶乘取模,后来其他题做不出来回头看这道题, 发现可以找规律,当p是合数的时候,P的因子全都可以在P前面的数字的因子里找到, 当p是素数的时候,(p-1)!%p = p-1,就尝试写了一下,2A: 因为4是个例外,怕还有其他例外情况,在100以内小规模…

Traffic Jam in Flower Town 题目链接: http://acm.hust.edu.cn/vjudge/contest/126546#problem/I Description Having returned from Sun City, Dunno told all his friends that every shorty may have a personal automobile. Immediately after that so many citizens to…

UVa Online Judge 工具網站   UVa中译题uHuntAlgorithmist Lucky貓的ACM園地,Lucky貓的 ACM 中譯題目 Mirror UVa Online Judge題目中譯!非常偉大的工作,請大家要心懷敬意! Ruby兔的ACM園地 UVa Online Judge題目中譯!非常偉大的工作,請大家要心懷感激! uHunt 這個站製作了一些網頁小工具, 可以查詢自己在UVa Online Judge的解題進度.簡單題列表.世界排名等等. 另外也整理了一套題庫,…

Submissions of online judge(1021) 问题描述 An online judge is a system to test programs in programming contests. The system can compile and execute codes, and test them with pre-constructed data. Submitted code may be run with restrictions, including tim…

C. Crazy Town   Crazy Town is a plane on which there are n infinite line roads. Each road is defined by the equation aix + biy + ci = 0, where ai and bi are not both equal to the zero. The roads divide the plane into connected regions, possibly of in…

(n-1)!/n 就是如果n为素数,就等于n-1else为0. 求素数表: Zball in Tina Town Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 833 Accepted Submission(s): 477 Problem Description Tina Town is a friendly place. People…

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=5391 Problem Description Tina Town is a friendly place. People there care about each other. Tina has a ball called zball. Zball time times )-th day. Tina want to know its size on the (n-)-th day mo…

Problem Description Ignatius is building an Online Judge, now he has worked out all the problems except the Judge System. The system has to read data from correct output file and user's result file, then the system compare the two files. If the two f…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Infoplane in Tina Town Time Limit: 14000/7000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 518    Accepted Submission(s): 74 Problem Description There i…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Zball in Tina Town Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 219    Accepted Submission(s): 144 Problem Description Tina Town i…

Big endian means the most significant byte stores first in memory. int a=0x01020304, if the cpu is big endian, data are store 01 02 03 04 in memory in increasing address. Below is a simple code to make the judgement. //execute the following cmd on th…