Eva would like to make a string of beads with her favorite colors so she went to a small shop to buy some beads. There were many colorful strings of beads. However the owner of the shop would only sell the strings in whole pieces. Hence Eva must chec…

可输入内容为0-9,a-z,A-Z. 输入: 第一行输入任意字符串: 第二行输入期望字符串. 输出: 如果第一行包含了所有期望字符串,输出yes和多余字符个数: 如果第一行不能完全包含期望字符串,输出缺失的字符个数. 思路: 记录第一行字符串每种字符个数,用HashTable数组记录: 遍历第二行字符串,遍历一个就在HashTable里对应的元素-1,如果HashTable<0,miss++: miss>0,则输出no,反之则输出yes. #include<cstdio> #inc…

Eva would like to make a string of beads with her favorite colors so she went to a small shop to buy some beads. There were many colorful strings of beads. However the owner of the shop would only sell the strings in whole pieces. Hence Eva must chec…

小红买些珠子做项链,但是卖家不肯拆散了卖,于是帮忙判断一下,某串珠子是否全部包含自己想要的珠子,如果是告诉她有多少多余的珠子,如果不是,又缺了那些珠子现在为了方便起见用"0-9""A----Z""a-z"范围内的字符来表示颜色.输入格式:每一个输出包含一个测试用例.每个测试用例分别在两行中先后给出摊主的珠串和小红想要的珠串,两串都不超过1000颗珠子输出格式:如果可以买,则在一行中输出"Yes"以及多余的珠子:反之输出&quo…

1092 To Buy or Not to Buy (20 分) Eva would like to make a string of beads with her favorite colors so she went to a small shop to buy some beads. There were many colorful strings of beads. However the owner of the shop would only sell the strings in…

小红想买些珠子做一串自己喜欢的珠串.卖珠子的摊主有很多串五颜六色的珠串,但是不肯把任何一串拆散了卖.于是小红要你帮忙判断一下,某串珠子里是否包含了全部自己想要的珠子?如果是,那么告诉她有多少多余的珠子:如果不是,那么告诉她缺了多少珠子. 为方便起见,我们用[0-9].[a-z].[A-Z]范围内的字符来表示颜色.例如在图1中,第3串是小红想做的珠串:那么第1串可以买,因为包含了全部她想要的珠子,还多了8颗不需要的珠子:第2串不能买,因为没有黑色珠子,并且少了一颗红色的珠子. 输入格式: 每个输入…

Source: PAT A1092 To Buy or Not to Buy (20 分) Description: Eva would like to make a string of beads with her favorite colors so she went to a small shop to buy some beads. There were many colorful strings of beads. However the owner of the shop would…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…