传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6324 Problem F. Grab The Tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1234    Accepted Submission(s): 779 Problem Description Little Q and…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6343 Problem L. Graph Theory Homework Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1536    Accepted Submission(s): 830 Problem Description Ther…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6341 Problem J. Let Sudoku Rotate Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1363    Accepted Submission(s): 717 Problem Description Sudoku i…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6342 Problem K. Expression in Memories Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2150    Accepted Submission(s): 772Special Judge Problem De…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6336 Problem E. Matrix from Arrays Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1711    Accepted Submission(s): 794 Problem Description Kazari…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6333 Problem B. Harvest of Apples Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 4043    Accepted Submission(s): 1560 Problem Description There a…

Function Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 652    Accepted Submission(s): 267 Sample Input 3 2 1 0 2 0 1 3 4 2 0 1 0 2 3 1 Sample Output Case #1: 4 Case #2: 4 Source 2017 Multi-U…

题意:给出一棵n个节点的树,每个节点有一个权值,Q和T玩游戏,Q先选一些不相邻的节点,T选剩下的节点,每个人的分数是所选节点的权值的异或和,权值大的胜出,问胜出的是谁. 题解: 话说,这题后面的边跟解的过程半毛钱关系没有,但是自己就是想不到,这博弈... 设sum为所有点权的异或和,A为先手得分,B为后手得分. 若sum=0,则A=B,故无论如何都是平局. 否则考虑sum二进制下最高的1所在那位,一定有奇数个点那一位为1.若先手拿走任意一个那一位为1的点,则B该位为0,故先手必胜. #inclu…

6324.Problem F. Grab The Tree 题目看着好难,但是题解说的很简单,写出来也很简单.能想出来就是简单的,想不出来就难(讲道理,就算是1+1的题目,看不出来就是难的啊). 和后面的东西一点关系都没有... 官方题解: 设sum为所有点权的异或和,A为先手得分,B为后手得分. 若sum=0,则A=B,故无论如何都是平局. 否则考虑sum二进制下最高的1所在那位,一定有奇数个点那一位为1.若先手拿走任意一个那一位为1的点,则B该位为0,故先手必胜. 时间复杂度O(n). 代码…

任意门:http://acm.hdu.edu.cn/showproblem.php?pid=6319 Problem A. Ascending Rating Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 5943    Accepted Submission(s): 2004 Problem Description Before…