For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is [1, 2, 3, 3, 4, 5, 10], for given ta…

找指定target的最左位置. class Solution { /** * @param nums: The integer array. * @param target: Target to find. * @return: The first position of target. Position starts from 0. */ public int binarySearch(int[] nums, int target) { if(nums == null) return -1;…

For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is [1, 2, 3, 3, 4, 5, 10], for given ta…

Binary search is a famous question in algorithm. For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If…

14. First Position of Target [easy] For a given sorted array (ascending order) and a targetnumber, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. Example If the array is […

For a given sorted array (ascending order) and a target number, find the first index of this number in O(log n) time complexity. If the target number does not exist in the array, return -1. 来源: http://www.lintcode.com/en/problem/first-position-of-tar…

Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (2016-02-10) For more problems and solutions, you can see my LintCode repository. I'll keep updating for full summary and better solutions. See cnblogs t…

CSharpGL(15)用GLSL渲染2种类型的文字 2016-08-13 由于CSharpGL一直在更新,现在这个教程已经不适用最新的代码了.CSharpGL源码中包含10多个独立的Demo,更适合入门参考. 为了尽可能提升渲染效率,CSharpGL是面向Shader的,因此稍有难度. 下载 这个示例是CSharpGL的一部分,CSharpGL已在GitHub开源,欢迎对OpenGL有兴趣的同学加入(https://github.com/bitzhuwei/CSharpGL) 血条 玩家头顶的…

一直直到bug-free.不能错任何一点. 思路不清晰:刷两天. 做错了,刷一天. 直到bug-free.高亮,标红. 185,OA(YAMAXUN)--- (1) findFirstDuplicate string in a list of string. import java.util.HashSet; import java.util.Set; public class Solution { public static void main(String[] args) { String[…

--------------------------------------------------------------- 本文使用方法:所有题目,只需要把标题输入lintcode就能找到.主要是简单的剖析思路以及不能bug-free的具体细节原因. ---------------------------------------------------------------- ------------------------------------------- 第九周:图和搜索. ---…