Binary Tree Traversals Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3475 Accepted Submission(s): 1555 Problem Description A binary tree is a finite set of vertices that is either empty or…
Problem Description 已知前序和中序 求后序 Input The input contains several test cases. The first line of each test case contains a single integer n (1<=n<=1000), the number of vertices of the binary tree. Followed by two lines, respectively indicating the pre…
A binary tree is a finite set of vertices that is either empty or consists of a root r and two disjoint binary trees called the left and right subtrees. There are three most important ways in which the vertices of a binary tree can be systematically…
/* Binary Tree Traversals Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4644 Accepted Submission(s): 2113 Problem Description A binary tree is a finite set of vertices that is either empty or co…
Binary Tree Traversals Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2681 Accepted Submission(s): 1178 Problem Description A binary tree is a finite set of vertices that is either empty or…
这里演示的二叉树为3层. 递归实现,先构造出一个root节点,先判断左子节点是否为空,为空则构造左子节点,否则进入下一步判断右子节点是否为空,为空则构造右子节点. 利用层数控制迭代次数. 依次递归第二段的内容. 下面是代码,很简单,耐心看看就懂了. package Construct; public class ConstructTree { private int count = 0; class Node { int i; Node left; Node right; public Node…