import java.math.BigInteger; import java.util.*; public class Main { public static void main(String []args) { Scanner cin=new Scanner(System.in); BigInteger a,b,c,d,m; int n; while(cin.hasNext()){ m=new BigInteger("1"); a=new BigInteger("1&…

大数的位数设置很坑,设成700会越界,设成800会超空间,最后设成了750居然就过了.... #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define LL long long using namespace std; /* * 完全大数模板 * 输出cin>>a * 输出a.print(…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.$F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n >…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12952    Accepted Submission(s): 4331 Problem Description A Fibonacci sequence…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14776    Accepted Submission(s): 4923   Problem Description A Fibonacci sequence is calculated by adding the previous two members…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1250 hdu1250: Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9442    Accepted Submission(s): 3096 Problem Description A Fibonacci…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5800    Accepted Submission(s): 1926 Problem Description A Fibonacci sequence is calculated by adding the previous two members the…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9394    Accepted Submission(s): 3065 Problem Description A Fibonacci sequence is calculated by adding the previous two members the…

Mathematician QSC Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 229    Accepted Submission(s): 114 Problem Description QSC dream of becoming a mathematician, he believes that everything in t…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12284    Accepted Submission(s): 4124 Problem Description A Fibonacci sequence is calculated by adding the previous two members t…

HDU 1588 Gauss Fibonacci(矩阵高速幂+二分等比序列求和) ACM 题目地址:HDU 1588 Gauss Fibonacci 题意:  g(i)=k*i+b;i为变量.  给出k,b,n,M,问( f(g(0)) + f(g(1)) + ... + f(g(n)) ) % M的值. 分析:  把斐波那契的矩阵带进去,会发现这个是个等比序列. 推倒: S(g(i)) = F(b) + F(b+k) + F(b+2k) + .... + F(b+nk) // 设 A = {1…

//  继续大数,哎.. Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your tas…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

题目 java做大数的题,真的是神器,来一道,秒一道~~~ import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @xqq */ public BigInteger an(int n) { BigInteger e; BigInteger a = BigInteger.valueOf(1); BigInteger b = BigInteger.valueOf(1); BigInteg…

Fibonacci Check-up Problem Description Every ALPC has his own alpc-number just like alpc12, alpc55, alpc62 etc.As more and more fresh man join us. How to number them? And how to avoid their alpc-number conflicted? Of course, we can number them one by…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1288 去买茶,需要正好的钱才行,另外花的钱的个数最多  其实是一个简单的贪心问题,小的多取一点,多的少取一点.反着想,算出超出部分数量. 代码: #include <stdio.h> #include <string.h> #include <math.h> #include <algorithm> #include <iostream> #incl…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2516 Problem Description 1堆石子有n个,两人轮流取.先取者第1次可以取任意多个,但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍.取完者胜.先取者负输出"Second win".先取者胜输出"First win".   Input 输入有多组.每组第1行是2<=n<2^31. n=0退出.   Output 先取者负输出&qu…

BUPT2017 wintertraining(16) #5 A HDU - 1021 题意 There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2). 输入n,若F(n)能被3整除,输出yes,否则no 题解 列一下前几项F(i)可以发现n%4==2则是yes,否则no. 代码 #include <cstdio> #include <cstring…

http://acm.hdu.edu.cn/showproblem.php?pid=1588 Problem Description Without expecting, Angel replied quickly.She says: "I'v heard that you'r a very clever boy. So if you wanna me be your GF, you should solve the problem called GF~. " How good an…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1250 思路:本题的Fibonacci数列是扩展的四阶的Fibonacci数列,用递推关系式求解即可. 题目提示,所求的Fibonacci数最多2500位,所以不能用已有的数据类型表示,可以采用数组存储数字,模拟加法. 由于没有给F(n)的n最大为多少,所以需要估计一下.经过反复测试,F(7000)约为2000位左右,如果设置数组长度为2500+1,则计算得到F(7500)的结果沾满了2500+1位(),…

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8194 Accepted Submission(s): 3410 Problem Description 任何一个大学生对菲波那契数列(Fibonacci numbers)应该都不会陌生,它是这样定义的: F(1)=1; F(2)=2; F(n)=F(n-1)+F(n-2)(n>=3); 所以…

http://acm.hdu.edu.cn/showproblem.php?pid=1848 题意:同nim,3堆,每次取的为fib数,n<=1000 #include <cstdio> #include <cstring> using namespace std; int f[1005], a[100]; bool b[20]; int main() { a[1]=1; a[2]=2; for(int i=3; i<=15; ++i) a[i]=a[i-1]+a[i-…

题目的大意就是求等差数列对应的Fibonacci数值的和,容易知道Fibonacci对应的矩阵为[1,1,1,0],因为题目中f[0]=0,f[1]=1,所以推出最后结果f[n]=(A^n-1).a,所以 f(g(i))= f(k*i+b)= (A^(k*i+b-1)).a,i从 0取到 n-1,取出公因式 A^(b-1)(因为矩阵满足分配率),然后所求结果可化为 A^(b-1) * (A^0 + A^k + A^2k +....+ A^(n-1)k),化到这里后难点就是求和了,一开始我尝试暴力…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

Description Without expecting, Angel replied quickly.She says: "I'v heard that you'r a very clever boy. So if you wanna me be your GF, you should solve the problem called GF~. " How good an opportunity that Gardon can not give up! The "Prob…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

http://acm.hdu.edu.cn/showproblem.php?pid=1250 大数斐波那契 %08d是什么东西,为什么我用flag交不上,唉,不刷大数了,没劲.暑假再讲. 就是交不上 #include <iostream> #include <stdio.h> #include <string.h> #include <stdlib.h> using namespace std; ][]; int main() { int n,k; mems…

Gauss Fibonacci Time Limit: 3000/1000 MS (Java/Others)     Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27    Accepted Submission(s): 5 Problem Description Without expecting, Angel replied quickly.She says: "I'v heard that you'r a ve…