Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 389    Accepted Submission(s): 100 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the ent…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, the total…

题目链接:HDU 5294 Tricks Device 题意:n个点,m条边.而且一个人从1走到n仅仅会走1到n的最短路径.问至少破坏几条边使原图的最短路不存在.最多破坏几条边使原图的最短路劲仍存在 思路: 1.跑一遍最短路.记录下全部最短路径,将这些最短路径的边以(0,1)(流量,容量)加到网络流中,跑一遍最大流 2.记录下的全部最短路径,再加到新的最短路的图中,边权为1,跑一遍最短路.m-最短路 就是答案 注意:有重边的情况 比方: 2 3 1 2 1 1 2 1 1 2 1 ans: 3…

第一次做最大流的题目- 这题就是堆模板 #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <cstdio> #include <cstdlib> #include <vector> #include <queue> using namespace std; typedef long long…

题意: 告诉我们有m个任务和k个机器.第i个任务需要ci天完成,最早从第ai天开始,最晚在第bi天结束.每台机器每天可以执行一个任务.问,是否可以将所有的任务都按时完成? 输入: 首行输入一个整数t,表示共有t组数据. 接下来,每组数据第一行输入两个整数k,m,表示共有k项任务,m台机器. 接下来k行,每行包括三个整数ci,ai,bi. 输出: 如果可以完成所有任务,输出——Case i: Yes 否则,输出——Case t: No 注意,每组输出占2行 这道题我如何也想不到是个最大流.即使我知…

Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 124    Accepted Submission(s): 27 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entr…

题目传送门 /* 题意:一无向图,问至少要割掉几条边破坏最短路,问最多能割掉几条边还能保持最短路 SPFA+Dinic:SPFA求最短路时,用cnt[i]记录到i最少要几条边,第二个答案是m - cnt[n] 最大流==最小割,套个Dinic模板,以后再理解算法... */ #include <cstdio> #include <algorithm> #include <cstring> #include <queue> #include <vecto…

Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu’s at the entrance…

最短路记录路径,同一时候求出最短的路径上最少要有多少条边, 然后用在最短路上的边又一次构图后求最小割. Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1584    Accepted Submission(s): 388 Problem Description Innocent Wu follows Dum…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 375    Accepted Submission(s): 98 Problem Description Innocent Wu follows Dumb Zh…

Productivity tips, tricks and hacks for academics (2015 edition) Contents Jump to: My philosophy: Optimize transaction costs. Don't work from home. Eliminate temptation to waste time. Salvage dead time with technology. Get rid of your TV. Taming emai…

Tricks Device 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5294 Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, th…

Yu-Gi-Oh! Time Limit: 2000ms Memory Limit: 65536KB This problem will be judged on HDU. Original ID: 538364-bit integer IO format: %I64d      Java class name: Main   "Yu-Gi-Oh!", also known as "Dueling Monsters", is a popular trading ca…

2015 Multi-University Training Contest 10 5406 CRB and Apple 1.排序之后费用流 spfa用stack才能过 //#pragma GCC optimize("O3") //#pragma comment(linker, "/STACK:1024000000,1024000000") #include<bits/stdc++.h> using namespace std; function<…

2015 Multi-University Training Contest 1 A.OO's Sequence 计算每个数的贡献 找出第\(i\)个数左边最靠右的因子位置\(lp\)和右边最靠左的因子位置\(rp\) 对答案的贡献就是\((rp-i)*(i-lp)\) 最后答案就是\(\sum_{i=1}^{n}(rp_i-i)*(i-lp_i)\) 预处理出来所有的因子,复杂度\(O(n\sqrt{10000})\) //#pragma GCC optimize("O3") //#…

---------- HDU 5288 OO’s Sequence 题意 给定一个数列(长度<$10^5$),求有多少区间[l,r],且区间内有多少数,满足区间内其它数不是他的约数. 数的范围$[1,10000]$.结果对$10^9+7$取模. Solution 首先可以预处理每个数的约数有哪些.对每个数存下它的位置有哪些. 然后可以枚举每一个位置,利用二分找到左边第一个是它约数的数,和右边第一个是他约数的数. 假设向左有L个数,向右有R个数.那么ans应该加上(L*R). 时间复杂度$O(n*…

tree Time Limit: 8000ms Memory Limit: 262144KB This problem will be judged on HDU. Original ID: 539064-bit integer IO format: %I64d      Java class name: Main   Given a rooted tree(node 1 is the root) with n nodes. The ithnode has a positive value vi…

本文首发于个人博客https://kezunlin.me/post/95370db7/,欢迎阅读最新内容! keras multi gpu training Guide multi_gpu_model import tensorflow as tf from keras.applications import Xception from keras.utils import multi_gpu_model import numpy as np G = 8 batch_size_per_gpu =…

Secrete Master Plan Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 429    Accepted Submission(s): 244 Problem Description Master Mind KongMing gave Fei Zhang a secrete master plan stashed in a…

2015 UESTC Winter Training #10 Northeastern Europe 2009 最近集训都不在状态啊,嘛,上午一直在练车,比赛时也是刚吃过午饭,状态不好也难免,下次比赛提前吃饭休息一会儿吧.. 一开始卡在B题,后来发现是题意理解错了,没有看见above,就是不可以回到原点,WA了5发也是够可惜的. 顺利地过了G题之后,就卡在了C题上,要T成doge了T T. A - Asteroids 三维凸包,等看计算几何之后再写 B - Business Center 有一座…

2015 UESTC Winter Training #8 The 2011 Rocky Mountain Regional Contest Regionals 2011 >> North America - Rocky Mountain 开始时貌似是UVAlive挂了,无论交什么都WA,后来转战HDU 这次水题比较多,其中B题据说有更加高级的方法. G题WA了两发,才发现竟然没有输出Case!!! 未完成:D F H I J A - Iterated Difference 水题,模拟迭代即可…

2015 UESTC Winter Training #7 2010-2011 Petrozavodsk Winter Training Camp, Saratov State U Contest 据说这套题写出3题就是金牌水平了... Problem D. Group Stage 足球比赛,现在有n(2<= n <=100)支球队.要从中选拔m(1<= m <=n-1)支球队,每支球队互相比赛一场,即比赛n*(n-1)/2场,胜者得3分,平局各得1分.最后从大到小列出排名,如果有…

2015 UESTC Winter Training #6 Regionals 2010 >> North America - Rocky Mountain A - Parenthesis 给一个长度不多于1000的表达式,只包含小写字母,加法运算,省略乘号的乘法运算和括号,输出去掉多余括号的表达式 括号匹配可以使用栈操作,只有两种情况可以去掉这一对括号: 左括号的左边是左边界.加法符号.左括号,并且右括号右边是有右边界.加法符号.右括号 如果括号内没有加法运算(括号内的括号里,也就是下一级括…

2015 UESTC Winter Training #4 Regionals 2008 :: Asia - Tehran 比赛开始时电脑死活也连不上WIFI,导致花了近1个小时才解决_(:зゝ∠)_ 未完成:B E F G H I A - String LD 给n(<=100)个互不相同的字符串(最长为100),然后进行stringld操作,就是每次操作把各个字符串的首个字符删去,直到 有字符串完全删去 存在两个字符串完全一致 问在最后一次操作之前有几次操作(PS:问法是在太奇怪了,不就是答案…

Game Rooms Time Limit: 4000/4000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status Your company has just constructed a new skyscraper, but you just noticed a terrible problem: there is only space to put one game room on each…

Root Time Limit: 30000/15000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 34    Accepted Submission(s): 6 Problem Description Given a number sum(1≤sum≤100000000),we have m queries which contains a pair (xi,yi) a…

官方解题报告:http://bestcoder.hdu.edu.cn/blog/2015-multi-university-training-contest-6-solutions-by-zju/ 表示很难看....orz 1003题      链接:http://acm.hdu.edu.cn/showproblem.php?pid=5355 Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K…

Hiking Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 97    Accepted Submission(s): 56 Special Judge Problem Description There are n soda conveniently labeled by 1,2,-,n. beta, their best fr…

OO's Sequence                                                          Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)                                                                                             T…

CRB and Tree                                                             Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)                                                                                            To…