题意: 如果所给序列的元素不是唯一的,则返回true,否则false. 思路: 哈希map解决. class Solution { public: bool containsDuplicate(vector<int>& nums) { unordered_map<int,int> mapp; ; i<nums.size(); i++) { if(mapp[nums[i]]) return true; ; } return false; } }; AC代码 python…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input: nums = [1,2,3,1], k = 3 Output:…

每天一算:Contains Duplicate II 描述 给出1个整形数组nums和1个整数k,是否存在索引i和j,使得nums[i] == nums[j] 且i和j之间的差不超过k Example 1: Input: nums = [1,2,3,1], k = 3 Output: true. Example 2: Input: nums = [1,0,1,1], k = 1 Output: true Example 3: Input: nums = [1,2,3,1,2,3], k = 2…

Given an array of integers and an integer k, return true if and only if there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. (Old Version) Given an array of integers and an i…

Given an array of integers, find out whether there are two distinct indices i and j in the array such that the absolute difference between nums[i] and nums[j] is at most t and the absolute difference between i and j is at most k. Example 1: Input: nu…

Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k. 这道题跟之前两道Contains Duplicate 包含重复值和Conta…

[python]Leetcode每日一题-存在重复元素3 [题目描述] 给你一个整数数组 nums 和两个整数 k 和 t .请你判断是否存在 两个不同下标 i 和 j,使得 abs(nums[i] - nums[j]) <= t ,同时又满足 abs(i - j) <= k . 如果存在则返回 true,不存在返回 false. 示例1: 输入:nums = [1,2,3,1], k = 3, t = 0 输出:true 示例2: 输入:nums = [1,0,1,1], k = 1, t…

Contains Duplicate II Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. Have you met this question in a…

题目 带重复元素的子集 给定一个可能具有重复数字的列表,返回其所有可能的子集 样例 如果 S = [1,2,2],一个可能的答案为: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 注意 子集中的每个元素都是非降序的 两个子集间的顺序是无关紧要的 解集中不能包含重复子集 挑战 你可以同时用递归与非递归的方式解决么? 解题 一个很简单的想法就是在上一题目中增加判断是否已经存在某个子集 class Solution: """ @param S: A…

1.题目描述 给定一个整数数组,判断是否存在重复元素. 如果任何值在数组中出现至少两次,函数返回 true.如果数组中每个元素都不相同,则返回 false. 2.示例 2.1 输入: [1,2,3,1] 输出: true 2.2 输入: [1,2,3,4] 输出: false 2.3 输入: [1,1,1,3,3,4,3,2,4,2] 输出: true 3.代码示例 3.1 首先,我们可以使用最暴力的解法,循环判断通过两次for循环进行嵌套,就可以解出来. class Solution { pu…